y(3y^2 - 12y + 4)
5*3y+1+12y-1 = 15y+1+12y-1 = 27y.
4(3y+4)
(4y + 1)(3y + 2)
12y + 2 or 2*(6y+ 1)
3y + 4z + 12y = 3y -3y -3y ------------------------- 4z + 12y = 0 divide everything by 4 z + 3y = 0 -3y -3y z = -3y
y(3y^2 - 12y + 4)
5*3y+1+12y-1 = 15y+1+12y-1 = 27y.
The given equation: =3x-4x plus 9xy-12y =3x-4x+9xy-12y =-x+9xy-12y =-x+3y(3y-4) Answer.
4(3y+4)
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To simplify the expression 2x + 3y + 4x + 9y, you first combine like terms. Adding the coefficients of x terms gives 2x + 4x = 6x. Similarly, adding the coefficients of y terms gives 3y + 9y = 12y. Therefore, the simplified expression is 6x + 12y.
(4y + 1)(3y + 2)
12y+3=9y-15 3y=-18 y=-6
12y + 2 or 2*(6y+ 1)
its 10x +9y +1z
Oh, dude, it's like you just gotta pull out the common factor, which in this case is 4. So, you're left with 4(x + 3y). And that's it, like, you're done. Easy peasy lemon squeezy.