The given equation:
=3x-4x plus 9xy-12y
=3x-4x+9xy-12y
=-x+9xy-12y
=-x+3y(3y-4)
Answer.
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z=pq
2z+6z+24=0 8z+24=0 8z= -24 z= - 3
Set up the equation and solve for z: 28 + z = 56 (next, subtract 28 from each side of the equaition to solve) z = 28
why will the equations x+14=37 and x-14=37 have different solutions for x
It is not possible to solve one equation in two unknowns (x and y). Two independent equations are required.