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∙ 11y agoyou add the divisor with the dividend then subtract your answer wiith your remainder
A 2 digit number divided by a four digit number, such as 2345, will leave the whole 2-digit number as a remainder. It cannot leave a remainder of 1.
No.
Divide the two-digit number by the one-digit number. If the remainder is zero then the 2-digit number is a multiple and if not, it is not.
81 is.
Yes- A remainder can be any number less than the dividend (the number by which the divisor is divided). An example of a 2 digit number is: 131/11=11 remainder 10.
9. The divisor must be greater than the remainder. A 1 digit divisor that is greater than 8 can only be 9.
Regardless of the dividend (the number being divided), no divisor can produce a remainder equal to, or greater than, itself..... dividing by 4 cannot result in a remainder of 5, for example, Therefore the only single-digit number which can return a remainder of 8 is 9. 35 ÷ 9 = 3 and remainder 8
A dividend is is a number to be divided and a divisor is a number to be divided into a dividend. Here the dividend is a three digit number and is divided by a one digit divisor. The quotient or result is a two digit number as stated. So in math terms, we can state that the dividend is a three digit number and that the divisor is a one digit number.
If 8 x divisor is 2 digit, divisor must be 12 or less If fist digit quotient x divisor is 3 digit, the first digit has to be 9 and the divisor is 12 9 x 12 = 108 8 x 12 = 96
you add the divisor with the dividend then subtract your answer wiith your remainder
A 2 digit number divided by a four digit number, such as 2345, will leave the whole 2-digit number as a remainder. It cannot leave a remainder of 1.
No.
You divide when there is a remainder the same as you divide when there is none. The only difference is that when you divide the last digit in the dividend, you will wither add a decimal point and 0 to the right of the digit and keep dividing, designate the leftover number as a remainder, or you will put the remainder over the divisor to show the remainder as a fraction. For example: 761 divided by 10 is 76 with a remainder of 1. You can write 76 R1, 76 1/10 or 76.1
There will be more than one answer. To have a remainder of 8, the divisor must be greater than 8. The only single digit greater than 8 is 9, so 9 must be the divisor. Since 8 is 1 less than 9, the dividend needs to be one less than a multiple of 9. Candidates are values of 3 digits, as the problem states. The lowest 3-digit number satisfying the condition is 107 (which is 9x12 - 1); the highest is 998 (which is 9x111 - 1). Some answers: 107 / 9 = 11 R8 125 / 9 = 13 R8 998 / 9 = 110 R8
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