Let's denote the two numbers as x and y. We can set up a system of equations to represent the given information: x + y = 500 and x - y = 156. By solving this system simultaneously, we can find the values of x and y. Adding the two equations eliminates y, giving us 2x = 656, so x = 328. Substituting x back into the first equation gives us y = 500 - 328 = 172. Therefore, the two numbers are 328 and 172.
Oh, dude, you're hitting me with some math here. So, if we have two numbers that add up to 500 and the difference between them is 156, we can set up a system of equations. Let's call the numbers x and y. We have x + y = 500 and x - y = 156. Solving these equations, we find that the numbers are 328 and 172. Math, man, it's wild.
Well, isn't that just a happy little math problem! Let's paint a picture with numbers. If we have two numbers that add up to 500 and have a difference of 156, we can create a simple equation to solve this. By adding half of the difference to the average of the two numbers, we find the two numbers are 328 and 172. Happy calculating!
500
They are from 11 squared to 22 squared making a total of 12 square numbers between 100 and 500
The prime numbers (factors) of 500 are: 2 and 5
500
There are infinitely many such numbers.
The 2 numbers that total 500 and are different by 156 are 328 and 172.
323 and 177
There are 156 such numbers.
Answer : In total there are 22 numbers.
177 and 323.
503 and 521.
500
501
To find the average of a set of numbers, you add all the numbers together and then divide by the total number of values. In this case, the sum of 124, 148, 207, and 21 is 500. Since there are 4 numbers in the set, you divide 500 by 4 to get an average of 125.
Profit is the difference between your income (3000) and your expenses (1500 + 500) So add 1500 and 500, and subtract THAT from 3000. The answer is your profit- on which you will pay taxes.
They are from 11 squared to 22 squared making a total of 12 square numbers between 100 and 500
Let's denote the two four-digit numbers as ABCD and EFGH, where A, B, C, D, E, F, G, H are digits. The sum of the two numbers is 8000, so we have 1000A + 100B + 10C + D + 1000E + 100F + 10G + H = 8000. The difference between the two numbers is 500, so we have 1000A + 100B + 10C + D - (1000E + 100F + 10G + H) = 500. By solving these two equations simultaneously, we find the two numbers are 4500 and 4000.