Let's denote the two numbers as x and y. We can set up a system of equations to represent the given information: x + y = 500 and x - y = 156. By solving this system simultaneously, we can find the values of x and y. Adding the two equations eliminates y, giving us 2x = 656, so x = 328. Substituting x back into the first equation gives us y = 500 - 328 = 172. Therefore, the two numbers are 328 and 172.
500
They are from 11 squared to 22 squared making a total of 12 square numbers between 100 and 500
The prime numbers (factors) of 500 are: 2 and 5
500
The 2 numbers that total 500 and are different by 156 are 328 and 172.
Let's denote the two numbers as x and y. We can set up a system of equations to represent the given information: x + y = 500 and x - y = 156. By solving this system simultaneously, we can find the values of x and y. Adding the two equations eliminates y, giving us 2x = 656, so x = 328. Substituting x back into the first equation gives us y = 500 - 328 = 172. Therefore, the two numbers are 328 and 172.
323 and 177
There are 156 such numbers.
Answer : In total there are 22 numbers.
177 and 323.
Let's denote the two four-digit numbers as ABCD and EFGH, where A, B, C, D, E, F, G, H are digits. The sum of the two numbers is 8000, so we have 1000A + 100B + 10C + D + 1000E + 100F + 10G + H = 8000. The difference between the two numbers is 500, so we have 1000A + 100B + 10C + D - (1000E + 100F + 10G + H) = 500. By solving these two equations simultaneously, we find the two numbers are 4500 and 4000.
503 and 521.
500
501
Profit is the difference between your income (3000) and your expenses (1500 + 500) So add 1500 and 500, and subtract THAT from 3000. The answer is your profit- on which you will pay taxes.
They are from 11 squared to 22 squared making a total of 12 square numbers between 100 and 500