Let the first number be x
So, x + (x+2) + [ 2 + (x +2)] = 48
x + x + 2 + 4 + x = 48
3x + 6 = 48
3x = 42
x = 14
The numbers are 14, 16 and 18
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The three consecutive even numbers with a sum of 138 are 44, 46 and 48.
It will always give an even number, as adding any amount of even numbers always results in an even number.
No. The sum of four consecutive integers is two odd numbers plus two even numbers which is an even number. 2001 is an odd number, therefore it cannot be the sum of four consecutive numbers.
Type your answer here... Dertermine three consecutive even numbers who's sum is 42?
There are no two consecutive even numbers whose sum is 100. It is easily proved.