-45
when you add the numbers it will add up to a multiple of 3. Lets say 12 1+2=3 or 36 3+6=9, they are all multiples of 3.
Well, one easy solution is to use the numbers: 0, 36, 28 : 36+28+0 = 64 36-28-0 = 8
36
Let's represent the four consecutive numbers as x, x+1, x+2, and x+3. The sum of these numbers is x + (x+1) + (x+2) + (x+3) = 4x + 6. We know that this sum equals 36, so we can set up the equation 4x + 6 = 36. Solving for x, we find x = 7. Therefore, the four consecutive numbers are 7, 8, 9, and 10.
36
-45
36
when you add the numbers it will add up to a multiple of 3. Lets say 12 1+2=3 or 36 3+6=9, they are all multiples of 3.
-3
114
11+12+13=36
Well, one easy solution is to use the numbers: 0, 36, 28 : 36+28+0 = 64 36-28-0 = 8
(3 x 3) + (5 x 5) = 9 + 25 = 34
36
-30
Let's represent the four consecutive numbers as x, x+1, x+2, and x+3. The sum of these numbers is x + (x+1) + (x+2) + (x+3) = 4x + 6. We know that this sum equals 36, so we can set up the equation 4x + 6 = 36. Solving for x, we find x = 7. Therefore, the four consecutive numbers are 7, 8, 9, and 10.