4x+2y-8=0 2y=8-4x y=4-2x slope= -2
3x + 2y = 8 2y=8-3x y=4-1.5x A quadratic has x^2 This is the equation of a line with negative slope.
The slope-intercept form of the equation of a line is y = mx + b, where m is the slope and b is the y-intercept. To put 3x - 2y = 16 in slope-intercept form just requires a little rearranging: 3x - 2y = 16 -2y = -3x + 16 (subtract 3x from both sides) y = 3/2x - 8 (divide all terms by -2) Now the equation is in slope-intercept form. The slope m is 3/2; the y-intercept is -8.
2y= 32 y=16
7x-2y=10 -2y=10-7x y=-5+(7/2)x y=(7/2)x-5 (Final answer)
-1/2
what is the slope of the line that has the equation 4x+2y=12?
4x+2y-8=0 2y=8-4x y=4-2x slope= -2
3x-2y+12 = 0 Rearrange the equation in the form of y = mx+c: y = 1.5x+6 Therefore the slope is 1.5 and the y intercept is 6
4x-2y = 5 -2y = -4x+5 y = 2x-2.5 The slope is 2 and the y intercept is -2.5
4x+2y = 6 2y = -4x+6 y = -2x+3 Slope = -2
5x - 2y = 10 2y = 5x - 10 y = 2.5x - 5......which is the equation in slope intercept form.
If: 4x-2y = 3 then y = 2x-1.5 whereas 2 is the slope and 1.5 is the y intercept
If: -3x+2y = 12 Then: y = 1.5x+6 in slope-intercept form
That will depend on what negative something equals which has not been given.
2y = 8x - 3 divide by 2 to both sidesy = 4x - 3/2 (this is the slope-intercept form of the equation, where slope is 4)The slope is 4.
5x+2y = 30 2y = -5x+30 y = -2.5x+15 Therfore the slope is 2.5 and y the intercept is 15.