2y = 6x - 8
y = 3x - 4
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m(slope) = 3
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4x+2y-8=0 2y=8-4x y=4-2x slope= -2
3x + 2y = 8 2y=8-3x y=4-1.5x A quadratic has x^2 This is the equation of a line with negative slope.
2y= 32 y=16
The slope-intercept form of the equation of a line is y = mx + b, where m is the slope and b is the y-intercept. To put 3x - 2y = 16 in slope-intercept form just requires a little rearranging: 3x - 2y = 16 -2y = -3x + 16 (subtract 3x from both sides) y = 3/2x - 8 (divide all terms by -2) Now the equation is in slope-intercept form. The slope m is 3/2; the y-intercept is -8.
7x-2y=10 -2y=10-7x y=-5+(7/2)x y=(7/2)x-5 (Final answer)