in england 15+ but in the usa version 12+
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x-a is a factor of the polynomial p(x),if p(a)=0.also,if x-a is a factor of p(x), p(a)=0.
You would factor it this way: 2 x 2 x 7 x m x m.
x^(3) - 12x^(2) + 35 x Factor out 'x' Hence x(x^(2) - 12x + 35) Factor the quadratic x(x - 5)(x - 7) Done!!!!!
First, you can take out the common factor "x".For what remains (the factor other than "x"), you can use the formula for the difference of two cubes.
X + Y (X + Y) ^2 = (X+Y)(X+Y) Factor = (X + Y)