First, you can take out the common factor "x".For what remains (the factor other than "x"), you can use the formula for the difference of two cubes.
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It is: (x-y)4
(x^2 + 4)(x^4 - 4x^2 + 16)
3x^4 - 12 = 3(x^4 - 4) = 3(x² + 2)(x² - 2)
(x - 2)(x + 2)(x2 - 2x + 4)(x2 + 2x + 4)
x^3 + 8 = (x + 2)(x^2 - 2x + 4)