Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
3 consecutive even integers whose sum is 396 are 130, 132 and 134.
24 + 25 + 26 = 75
The numbers are 23, 24 and 25.
The integers are are 41, 42 and 43.
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
117/3 = 39, so the three consective odd integers whose sum is 117 are 37, 39, and 41.
117
It need not be. 2 and 3 are consecutive integers and their sum is 5, not 31.
Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.
201
They are are 62, 63 and 64.
3 consecutive even integers whose sum is 396 are 130, 132 and 134.
The sum of even integers cannot end with 9. why not
4 and 5
73,74,75
The integers are 16, 17 and 18.