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What are the three consecutive integers of 354?
117, 118 and 119.
What are the three consecutive odd integers with the sum of 117?
The numbers are 37, 39 and 41.
What are two consecutive integers of the square root of 117?
The square roots of 117 are irrational numbers and so are not two integers - consecutive or otherwise.
What are 3 consecutive integers that have a sum of 117?
38, 39, 40
Three conecutive integers whos sum is 117?
You can find those by trial and error. You can also write an equation for the three consecutive integers, and solve it. If the first number is "n", the others are "n + 1" and "n + 2". By solving the equation for "n", you get the first of the three numbers.
Find three Consecutive odd integers whose sum is 117?
117/3 = 39, so the three consective odd integers whose sum is 117 are 37, 39, and 41.
What are three consecutive integers whose sum equals -354?
(-117)+(-118)+(-119)=(-354)
What are the three consecutive integers of 354?
117, 118 and 119.
Find 3 consecutive even integers whose sum is -114?
117
What are the three consecutive odd integers with the sum of 117?
The numbers are 37, 39 and 41.
What are two consecutive integers of the square root of 117?
The square roots of 117 are irrational numbers and so are not two integers - consecutive or otherwise.
What are 3 consecutive integers that have a sum of 117?
38, 39, 40
Find three consecutive integers whose sum is 348?
These are really simple to solve. Just divide by 3 and that gives you your middle integer. In this case 348/3 = 116 so the trio are 115, 116 and 117.
Two consecutive odd integers whose sum is 117?
answer is : 58,59working: x= first number, x + 1= second numberx + x + 1 =1172x= 116x= 58
Three conecutive integers whos sum is 117?
You can find those by trial and error. You can also write an equation for the three consecutive integers, and solve it. If the first number is "n", the others are "n + 1" and "n + 2". By solving the equation for "n", you get the first of the three numbers.
Ind three consecutive odd integers that have a sum of 123?
x is lowest of the integers so x + (x + 2) + (x + 4) = 123 ie 3x + 6 = 123 so 3x = 117 and x = 39, so integers are 39, 41 and 43
Three consecutive odd numbers add up to 117?
lET THE INTEGERS BE n < n+2 , N+ 4 Hence their sum is n + n + 2 + n + 4 = 117 Adding 3n + 6 = 117 Subtract '6' from both sides 3n = 111 Divide both sides by '3' n = 37 n + 2 = 39 n + 4 = 41 Hence the consecutive odd integers are 37,39, & 41.
