If the sum of its' digits are divisible by 3 for all numbers greater than 9.
U={whole number greater than 10 but smaller than 30 } X={numbers divisible by 3 } Y Odd numbers
Three of them.
There is only one number that can be divisible by both 3 and 4 yet not greater than 20, 12.
Because many of them are divisible by smaller odd numbers. For example 35 is divisible by 5 and so 35 cannot be a prime number.
If the sum of its' digits are divisible by 3 for all numbers greater than 9.
U={whole number greater than 10 but smaller than 30 } X={numbers divisible by 3 } Y Odd numbers
402. It is the first number after 400 for which the digital root (the sum of its digits) is divisible by 3. The digital root being divisible by 3 is a test for divisibility by 3.
78,84,90,96
Three of them.
There is only one number that can be divisible by both 3 and 4 yet not greater than 20, 12.
7x3 = 21 All numbers from 1-400 (399 total) that are factors of 21: 399/21 = 19
Because many of them are divisible by smaller odd numbers. For example 35 is divisible by 5 and so 35 cannot be a prime number.
All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.
Yes; all numbers that are divisible by 9 are divisible by 3.
9 is greater than 6 and divisible by 3.
5, 7, a bunch of numbers that are odd are not divisible by 3. numbers that are divisible by three can have all their numbers added together and come out with a number that is divisible by 3.