In algebra, x can have any value as the letter is used to represent any number that is unknown until solved.
e.g. 2x=4
x=2
In Roman Numerals, X is 10.
9
In ordered pair forms (0,-5) (1,-4) (2,-3) The first values are the x values and the second values are the y values.
No, the equation ( x^5 ) is not equivalent to ( x^{-1} \cdot 5 - 1 ). The expression ( x^5 ) represents ( x ) raised to the power of 5, while ( x^{-1} \cdot 5 - 1 ) implies a different operation involving the reciprocal of ( x ) multiplied by 5, then subtracting 1. These two expressions have different forms and will yield different results for most values of ( x ).
No, (5x) and (x^5) do not represent the same expression. (5x) means 5 multiplied by the variable (x), while (x^5) means (x) raised to the fifth power. These expressions have different meanings and will yield different values for any given value of (x).
The equation ( y - x - 5 = 0 ) can be rewritten as ( y = x + 5 ). To create a table of values, you can choose various ( x ) values and calculate the corresponding ( y ) values. For example, if ( x = 0 ), then ( y = 5 ); if ( x = 1 ), then ( y = 6 ); and if ( x = -1 ), then ( y = 4 ). A correct table might look like this: | ( x ) | ( y ) | |-------|-------| | 0 | 5 | | 1 | 6 | | -1 | 4 |
10.
9
In ordered pair forms (0,-5) (1,-4) (2,-3) The first values are the x values and the second values are the y values.
One, the value five.
No, the equation ( x^5 ) is not equivalent to ( x^{-1} \cdot 5 - 1 ). The expression ( x^5 ) represents ( x ) raised to the power of 5, while ( x^{-1} \cdot 5 - 1 ) implies a different operation involving the reciprocal of ( x ) multiplied by 5, then subtracting 1. These two expressions have different forms and will yield different results for most values of ( x ).
No, (5x) and (x^5) do not represent the same expression. (5x) means 5 multiplied by the variable (x), while (x^5) means (x) raised to the fifth power. These expressions have different meanings and will yield different values for any given value of (x).
The equation ( y - x - 5 = 0 ) can be rewritten as ( y = x + 5 ). To create a table of values, you can choose various ( x ) values and calculate the corresponding ( y ) values. For example, if ( x = 0 ), then ( y = 5 ); if ( x = 1 ), then ( y = 6 ); and if ( x = -1 ), then ( y = 4 ). A correct table might look like this: | ( x ) | ( y ) | |-------|-------| | 0 | 5 | | 1 | 6 | | -1 | 4 |
8
You are asking, in effect, what number is 5; the answer is, 5 is 5.
5
The values that make each of the factors zero. In other words, you need to solve:x - 2 = 0 and: x - 5 = 0
2 or 5