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In algebra, x can have any value as the letter is used to represent any number that is unknown until solved.

e.g. 2x=4

x=2

In Roman Numerals, X is 10.

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Q: What are 5 different values of x?
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Related questions

How many different combinations of x-values and y-values could satisfy the equation - x plus y equals 5?

10.


What is the constant term in the equation y equals 4x-5?

9


What are three different ordered pairs that are solutions of the equation Y equals x 5?

In ordered pair forms (0,-5) (1,-4) (2,-3) The first values are the x values and the second values are the y values.


How many different values for x make the equation x equals 5 true?

One, the value five.


What is the value of the rational expression x plus 4 divided by 4 minus x?

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What values of x is 5?

You are asking, in effect, what number is 5; the answer is, 5 is 5.


If the domain of f(x)-x2 is integer values of x such that -3-x?

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If the factors of a polynomial are x-2 and x-5 what values of x make that polynomial 0?

The values that make each of the factors zero. In other words, you need to solve:x - 2 = 0 and: x - 5 = 0


If the factors of a polynomial are x - 2 and x - 5 what values of x make that polynomial 0?

2 or 5


What are the possible values for x if x 2 plus 5 x equals 6?

x (x+5) = 6 X equals 1.


How do you solve y equals -5x-1?

-4


How can you test the equivalence of two expressions using tables and graphs?

You can test for inequality but not for equality.You can take different values of the independent variable or argument of the expression (usually denoted by x), and calculate the dependent variable or the value of the expression (usually denoted by y). These can be tabulated or shown on a graph. If the y-values for the same x-values are different, then the two expressions are different. But even if they all match perfectly, you cannot say that they are equivalent because there could be other x-values - which you did not test - for which the y-values are different.For example, considerf(x) = x^2 + 4andg(x) = x^3 - 3x^2 - 5x + 4then f(-1) = 5 = g(-1)f(0) = 4 = g(0)and f(5) = 29 = g(5)but for any other integer value of x, the values of the two expressions are different. However, your test did not pick that up.You could increase the number of points tested but there will be other expressions such that the two can match at any number of selected points and still be different elsewhere.