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Let the three consecutive numbers be ( x ), ( x + 1 ), and ( x + 2 ). Their sum can be expressed as ( x + (x + 1) + (x + 2) = 3x + 3 ). Setting this equal to 3000 gives the equation ( 3x + 3 = 3000 ). Solving for ( x ) yields ( x = 999 ), so the three consecutive numbers are 999, 1000, and 1001.

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AnswerBot

1w ago

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