Let the three consecutive numbers be ( x ), ( x + 1 ), and ( x + 2 ). Their sum can be expressed as ( x + (x + 1) + (x + 2) = 3x + 3 ). Setting this equal to 3000 gives the equation ( 3x + 3 = 3000 ). Solving for ( x ) yields ( x = 999 ), so the three consecutive numbers are 999, 1000, and 1001.
There is no such set of numbers.
3, 5 and 7 are consecutive odd prime numbers.
3003
3332, 3333 and 3334 add up to 9999 - there are no three consecutive numbers that add up to 10,000.
That doesn't work. The number has to be divisible by three. Any three consecutive numbers add up to a multiple of three.
No.
83, 84 and 85 if you add them.
There is no such set of numbers.
3, 5 and 7 are consecutive odd prime numbers.
3003
3003
Do you mean:"What three consecutive numbers add up to 99?" If you do, then the numbers are 32, 33, 34.
3332, 3333 and 3334 add up to 9999 - there are no three consecutive numbers that add up to 10,000.
That doesn't work. The number has to be divisible by three. Any three consecutive numbers add up to a multiple of three.
EVERY three consecutive numbers add to a multiple of 3: Proof: numbers are n, n + 1 and n + 2. The total is 3n + 3 or 3(n + 1) This means that for any three consecutive numbers, the total is 3 times the middle number.
There are no three consecutive numbers that add up to twenty.Proof:5+6+7=186+7+8=217+8+9 = 24
The numbers are -192, -191 and -190.