120% (or -120%) is a fraction. As soon as you start working with fractions, the concept of consecutive begins to lose any relevance.
For example, what number would you consider to be consecutive to 0.75?
0.76 or 0.751 or 0.7501, or 4/4 or 7/8 [=(6+1)/8] etc?
The numbers are 120, 121 and 122.
The numbers are 39, 40 and 41.
The numbers are 38, 40 and 42.
None that are all odd numbers. But, there are two sets of three consecutive numbers containing a mix of even/odd that add up to 120. They are 39, 40 and 41 and also 38, 40 and 42.
The numbers are 116, 118 and 120.
The numbers are 120, 121 and 122.
There are two consecutive even integers. The numbers are 118 and 120.
The numbers are 39, 40 and 41.
The numbers are 38, 40 and 42.
3*4*10
44
Let the numbers be 'n' , 'n+1' & 'n+2' Hence adding n + n+1 + n + 2 = 120 3n + 3 = 120 3n = 117 n = 39 Hence n + 1 = 40 n + 2 = 41 So the three consecutive numbers are ;- 39,40,& 41.
None that are all odd numbers. But, there are two sets of three consecutive numbers containing a mix of even/odd that add up to 120. They are 39, 40 and 41 and also 38, 40 and 42.
The numbers are 116, 118 and 120.
1,4,5
The consecutive integers are 39, 40, and 41. To solve this algebraically, note that consecutive numbers can be indicated by the variables x, x+1, and x+2. For the sum x + (x+1) + (x+2) = 120, 3x +3 = 120 3x= 117 x= 39, followed by 40 and 41 39+40+41 = 120
A rectangular number, also known as a pronic number, is the product of two consecutive integers. To determine if 93, 120, and 301 are rectangular numbers, we can check if they can be expressed as ( n(n+1) ) for some integer ( n ). 93 can be expressed as ( 9 \times 10 ), which is not the product of consecutive integers. 120 can be expressed as ( 10 \times 12 ), which is also not consecutive. 301 cannot be expressed as a product of two consecutive integers either. Therefore, none of these numbers are rectangular numbers.