The expression "W w 2 and W w w" seems to refer to some form of notation or representation that is unclear. If "W" and "w" represent specific values or variables, please provide their meanings or numerical representations for clarification. Otherwise, five arbitrary numbers between two unspecified values can be any set of integers or decimals within that range.
That is the property of infinite density of rational numbers. If x and y are any two rational numbers then w = (x + y)/2 is a rational number between them. And then there is a rational number between x and w. This process can be continued without end.
½W - 3 and ½W + 3 (½W - 3) + (½W + 3) = ½W + ½W - 3 + 3 = W |(½W - 3) - (½W + 3)| = |½W - 3 - ½W - 3| = |½W - ½W - 3 - 3| = |-6| = 6 (The difference between two numbers can be calculated by subtracting one from the other and ignoring the sign; |n| is the value of n ignoring the sign.)
W
Five 'w' could signify the five common question words:whowhatwhenwhywhere
As w and w are the same number, there are no numbers between w and w. However, if it is inclusive of the limits, (ie "between w and w inclusive"), then there is only 1 number w, which to be a multiple of 4 6 and 8 must be a multiple of their lowest common multiple (lcm) which is 24; ie all multiples of 24, namely w is one of: 24, 48, 72, 96, 120, 144, 168, ...
The number (w +W)/2. To find a halfway point (which is also the average), add the numbers together and divide by 2.
That is the property of infinite density of rational numbers. If x and y are any two rational numbers then w = (x + y)/2 is a rational number between them. And then there is a rational number between x and w. This process can be continued without end.
No.
½W - 3 and ½W + 3 (½W - 3) + (½W + 3) = ½W + ½W - 3 + 3 = W |(½W - 3) - (½W + 3)| = |½W - 3 - ½W - 3| = |½W - ½W - 3 - 3| = |-6| = 6 (The difference between two numbers can be calculated by subtracting one from the other and ignoring the sign; |n| is the value of n ignoring the sign.)
The formula for the perimeter of a rectangle is 2(L + W), where L is the length and W is the width. Then 16 = 2(L + W) : 8 = L + W. And L = W - 8, or W = L - 8 So, if you were dealing integers, you can choose any two numbers between 1 and 7 so that the numbers when added equal 8.
W
Five 'w' could signify the five common question words:whowhatwhenwhywhere
Oh, what a happy little math problem we have here! To factor w^2 + 8w + 12, we're looking for two numbers that multiply to 12 and add up to 8. Those numbers are 2 and 6. So, we can rewrite the equation as (w + 2)(w + 6). Just like that, we've created a beautiful factorization!
As w and w are the same number, there are no numbers between w and w. However, if it is inclusive of the limits, (ie "between w and w inclusive"), then there is only 1 number w, which to be a multiple of 4 6 and 8 must be a multiple of their lowest common multiple (lcm) which is 24; ie all multiples of 24, namely w is one of: 24, 48, 72, 96, 120, 144, 168, ...
There are infinitely many rational numbers between 2 and 3. This is because rational numbers are numbers that can be expressed as a fraction of two integers, and there are infinitely many integers between any two integers. Therefore, there are an infinite number of fractions between 2 and 3 that can be written in the form of (n/d) where n and d are integers.
Perimeter = 2*L + 2*W Area = L*W L = Area / W Perimeter = 2*Area / W + 2*W W * Perimeter = 2*Area + 2*W^2 Let A=area, and P= perimeter. 0=2W^2-PW+2A Quadratic formula: W= (P + root(P^2-16A))/4 or W= (P - root(P^2-16A))/4 Once you have W, L is simply A/W. Have fun, and maybe include some numbers to work with next time.
Suppose W/3 is the even integer X. Then the numbers are (X-2, X , X+2)If W/3 is not an even integer then there is no solution.