The expression "W w 2 and W w w" seems to refer to some form of notation or representation that is unclear. If "W" and "w" represent specific values or variables, please provide their meanings or numerical representations for clarification. Otherwise, five arbitrary numbers between two unspecified values can be any set of integers or decimals within that range.
That is the property of infinite density of rational numbers. If x and y are any two rational numbers then w = (x + y)/2 is a rational number between them. And then there is a rational number between x and w. This process can be continued without end.
½W - 3 and ½W + 3 (½W - 3) + (½W + 3) = ½W + ½W - 3 + 3 = W |(½W - 3) - (½W + 3)| = |½W - 3 - ½W - 3| = |½W - ½W - 3 - 3| = |-6| = 6 (The difference between two numbers can be calculated by subtracting one from the other and ignoring the sign; |n| is the value of n ignoring the sign.)
W
Five 'w' could signify the five common question words:whowhatwhenwhywhere
To determine what numbers go into "W," we need to know the value or context of "W." Generally, if "W" represents a whole number, its divisors are the numbers that can divide it evenly without leaving a remainder. For example, if W is 12, the numbers that equally go into it are 1, 2, 3, 4, 6, and 12. Please provide the value of W for a more specific answer.
The number (w +W)/2. To find a halfway point (which is also the average), add the numbers together and divide by 2.
That is the property of infinite density of rational numbers. If x and y are any two rational numbers then w = (x + y)/2 is a rational number between them. And then there is a rational number between x and w. This process can be continued without end.
½W - 3 and ½W + 3 (½W - 3) + (½W + 3) = ½W + ½W - 3 + 3 = W |(½W - 3) - (½W + 3)| = |½W - 3 - ½W - 3| = |½W - ½W - 3 - 3| = |-6| = 6 (The difference between two numbers can be calculated by subtracting one from the other and ignoring the sign; |n| is the value of n ignoring the sign.)
No.
The formula for the perimeter of a rectangle is 2(L + W), where L is the length and W is the width. Then 16 = 2(L + W) : 8 = L + W. And L = W - 8, or W = L - 8 So, if you were dealing integers, you can choose any two numbers between 1 and 7 so that the numbers when added equal 8.
W
Five 'w' could signify the five common question words:whowhatwhenwhywhere
Oh, what a happy little math problem we have here! To factor w^2 + 8w + 12, we're looking for two numbers that multiply to 12 and add up to 8. Those numbers are 2 and 6. So, we can rewrite the equation as (w + 2)(w + 6). Just like that, we've created a beautiful factorization!
To determine what numbers go into "W," we need to know the value or context of "W." Generally, if "W" represents a whole number, its divisors are the numbers that can divide it evenly without leaving a remainder. For example, if W is 12, the numbers that equally go into it are 1, 2, 3, 4, 6, and 12. Please provide the value of W for a more specific answer.
As w and w are the same number, there are no numbers between w and w. However, if it is inclusive of the limits, (ie "between w and w inclusive"), then there is only 1 number w, which to be a multiple of 4 6 and 8 must be a multiple of their lowest common multiple (lcm) which is 24; ie all multiples of 24, namely w is one of: 24, 48, 72, 96, 120, 144, 168, ...
There are infinite rational numbers between 2 and 3.Explanation:Let us write a few decimal numbers between 2 and 3: 2.01, 2.001, 2.0001,.., 2.4, 2.90 etc. Just change digits after the decimal point and this way we can write infinite decimal numbers between 2 and 3. And each decimal number can be expressed in the form of p/q(rational number)2.01 = 201/1002.001 = 2001/1000... 2.4 = 24/10 and so on.So there are infinitely many rational numbers b/w 2 and 3.
Perimeter = 2*L + 2*W Area = L*W L = Area / W Perimeter = 2*Area / W + 2*W W * Perimeter = 2*Area + 2*W^2 Let A=area, and P= perimeter. 0=2W^2-PW+2A Quadratic formula: W= (P + root(P^2-16A))/4 or W= (P - root(P^2-16A))/4 Once you have W, L is simply A/W. Have fun, and maybe include some numbers to work with next time.