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Oh, what a happy little math problem we have here! To factor w^2 + 8w + 12, we're looking for two numbers that multiply to 12 and add up to 8. Those numbers are 2 and 6. So, we can rewrite the equation as (w + 2)(w + 6). Just like that, we've created a beautiful factorization!
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How can you factor this trinomial w2 plus 5w - 14?
(w + 7)(w - 2)
Reduce the fraction w2 plus 5w plus 6 over w2-w-12?
Ah, math time, my favorite! To reduce the fraction w^2 + 5w + 6 over w^2 - w - 12, first factor both the numerator and the denominator. The numerator factors into (w + 2)(w + 3), and the denominator factors into (w + 3)(w - 4). Cancel out the common factor of (w + 3) in both the numerator and the denominator, leaving you with (w + 2) over (w - 4). Voilà!
What is ww plus 97 equals 133?
It is either a linear equation in a variable ww or a quadratic equation in a variable w, (with ww denoting w2).
A triangle is 3cm wider than it tall the area is 27cm2find the width?
Area of triangle = 0.5 * width * height So 27 = 0.5 * w * (w-3) or 54 = w2 - 3w ie w2 - 3w - 54 = 0 w2 - 9w + 6w - 54 = 0 w(w - 9) + 6(w - 9) = 0 ie (w - 9)(w + 6) = 0 So w = 9 or w = -6 But since w is a width, it must be positive and so w = 9 cm.
What are the dimensions of rectangle if the diagonal is 13cm?
The length of the diagonal is not enough to determine the dimensions of the rectangle. Take any length W such that 0<W<sqrt(132/2) that is, 0<W<9.192 cm. And let L = sqrt(132 - W2) cm. Then 9.192<L<13 so that any combination of W and L is unique. There are infinitely many possible values for W and so infinitely many different combinations for W and L. That is, infinitely many rectangles whose width is W cm and length is L cm. And, since, L2 = 132 - W2, L2 + W2 = 132 so the diagonal is 13 cm.
What is the factor of w2 8w 16?
42/6
How do you factor W2-8W-28?
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: 4 plus or minus 2 times the square root of 11x = 10.6332495807108x = -2.6332495807108
How do you factor w2-14x 24?
(w - 12)(w - 2)
How can you factor this trinomial w2 plus 5w - 14?
(w + 7)(w - 2)
What is the factored form of w2 plus 18w plus 77?
w2+18w+77 = (w+7)(w+11) when factored
How do you factor trinomials?
you do 2 sets of parenthesis and check it. for example: w2(w squared)-7w-8 (w+1) (w-8) *if you add 1w and -8w you will get -7w, which is what they want you to get. and w & w multiply to get w2(w squared), which is also what the factoring wants. another example: 3w2 (3w squared)+2-8 (3w-4) (w+2) *same thing applies with 3w x w = 3w2, and -4 +2=2, which is the answer. use this theory in all of them, unless there is a greatest common factor (GCF).
What is 3w-9w when w2?
The answer is -12
How do you factor w2 18w 81?
(w + 9)(w + 9)
Reduce the fraction w2 plus 5w plus 6 over w2-w-12?
Ah, math time, my favorite! To reduce the fraction w^2 + 5w + 6 over w^2 - w - 12, first factor both the numerator and the denominator. The numerator factors into (w + 2)(w + 3), and the denominator factors into (w + 3)(w - 4). Cancel out the common factor of (w + 3) in both the numerator and the denominator, leaving you with (w + 2) over (w - 4). Voilà!
How do you solve w2 plus 49 equals 0?
If by w2 you mean "w squared", then it cannot be done. BECAUSE w2 + 49 = 0 w2 +49 - 49 = 0 - 49 w2 = -49 w2 means a number multiplied by itself. Any number multplied by itself will result in a POSITIVE number. positive x positive = positive negative x negative = negatve
Need the work and answer for this math problem w2 plus 30 w plus 81 using vocabulary words factor gfc prime factor perfect square and grouping?
The grouping of the factors of w^2 + 30w + 81 (a perfect square) is (w + 27) and (w + 3)3 is a prime factor of 27, 30 and 81 but without two terms to compare, there won't be a GCF (not gfc)
How do you factor 36v2-w2?
There is a formula for the "difference of squares." In this case, the answer is (6v + w)(6v - w)
