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Oh, what a happy little math problem we have here! To factor w^2 + 8w + 12, we're looking for two numbers that multiply to 12 and add up to 8. Those numbers are 2 and 6. So, we can rewrite the equation as (w + 2)(w + 6). Just like that, we've created a beautiful factorization!
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How can you factor this trinomial w2 plus 5w - 14?
(w + 7)(w - 2)
Reduce the fraction w2 plus 5w plus 6 over w2-w-12?
Ah, math time, my favorite! To reduce the fraction w^2 + 5w + 6 over w^2 - w - 12, first factor both the numerator and the denominator. The numerator factors into (w + 2)(w + 3), and the denominator factors into (w + 3)(w - 4). Cancel out the common factor of (w + 3) in both the numerator and the denominator, leaving you with (w + 2) over (w - 4). Voilà!
What is ww plus 97 equals 133?
It is either a linear equation in a variable ww or a quadratic equation in a variable w, (with ww denoting w2).
A triangle is 3cm wider than it tall the area is 27cm2find the width?
Area of triangle = 0.5 * width * height So 27 = 0.5 * w * (w-3) or 54 = w2 - 3w ie w2 - 3w - 54 = 0 w2 - 9w + 6w - 54 = 0 w(w - 9) + 6(w - 9) = 0 ie (w - 9)(w + 6) = 0 So w = 9 or w = -6 But since w is a width, it must be positive and so w = 9 cm.
What are the dimensions of rectangle if the diagonal is 13cm?
The length of the diagonal is not enough to determine the dimensions of the rectangle. Take any length W such that 0<W<sqrt(132/2) that is, 0<W<9.192 cm. And let L = sqrt(132 - W2) cm. Then 9.192<L<13 so that any combination of W and L is unique. There are infinitely many possible values for W and so infinitely many different combinations for W and L. That is, infinitely many rectangles whose width is W cm and length is L cm. And, since, L2 = 132 - W2, L2 + W2 = 132 so the diagonal is 13 cm.
What is the factor of w2 8w 16?
42/6
How do you factor W2-8W-28?
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: 4 plus or minus 2 times the square root of 11x = 10.6332495807108x = -2.6332495807108
How do you factor w2-14x 24?
(w - 12)(w - 2)
How can you factor this trinomial w2 plus 5w - 14?
(w + 7)(w - 2)
What is the factored form of w2 plus 18w plus 77?
w2+18w+77 = (w+7)(w+11) when factored
How do you factor trinomials?
you do 2 sets of parenthesis and check it. for example: w2(w squared)-7w-8 (w+1) (w-8) *if you add 1w and -8w you will get -7w, which is what they want you to get. and w & w multiply to get w2(w squared), which is also what the factoring wants. another example: 3w2 (3w squared)+2-8 (3w-4) (w+2) *same thing applies with 3w x w = 3w2, and -4 +2=2, which is the answer. use this theory in all of them, unless there is a greatest common factor (GCF).
What is 3w-9w when w2?
The answer is -12
How do you factor w2 18w 81?
(w + 9)(w + 9)
Reduce the fraction w2 plus 5w plus 6 over w2-w-12?
Ah, math time, my favorite! To reduce the fraction w^2 + 5w + 6 over w^2 - w - 12, first factor both the numerator and the denominator. The numerator factors into (w + 2)(w + 3), and the denominator factors into (w + 3)(w - 4). Cancel out the common factor of (w + 3) in both the numerator and the denominator, leaving you with (w + 2) over (w - 4). Voilà!
How can I locate my HSA contributions on my W2 form?
You can find your HSA contributions on your W2 form in Box 12 with the code "W."
How do you solve w2 plus 49 equals 0?
If by w2 you mean "w squared", then it cannot be done. BECAUSE w2 + 49 = 0 w2 +49 - 49 = 0 - 49 w2 = -49 w2 means a number multiplied by itself. Any number multplied by itself will result in a POSITIVE number. positive x positive = positive negative x negative = negatve
Need the work and answer for this math problem w2 plus 30 w plus 81 using vocabulary words factor gfc prime factor perfect square and grouping?
The grouping of the factors of w^2 + 30w + 81 (a perfect square) is (w + 27) and (w + 3)3 is a prime factor of 27, 30 and 81 but without two terms to compare, there won't be a GCF (not gfc)
