any of the sequence 8, 16, 24, 32, 40, ....
Each number is half the previous number. The series formula is a(n) = 32 *(½)n⁻¹ 32, 16, 8, 4, 2, 1, 0.5 The next three numbers in the sequence are : 0.25, 0.125, 0.0625
32
18, 24.5 and 32.
They are 1/2 the previous term and so the next term will be -32
32
9 (between 8 and 16).
To find the missing number in the sequence 32, 52, 74, 112, 135, we need to identify the pattern or rule governing the sequence. The differences between consecutive numbers are 20, 22, 38, and 23, respectively. The pattern is not immediately clear, but it appears that the differences are not following a simple arithmetic progression. One possible explanation could be that the differences are increasing by odd numbers (2, 16, 15), so the next difference could be 15. Adding 15 to the last number in the sequence (135) gives us 150 as a potential missing number.
a sequence of shifted geometric numbers
1024 = 45
32
21
The missing number is 34. The progressive difference between the numbers doubles: 4 + 2 = 6 6 + 4 = 10 10 + 8 = 18 18 + 16 = 34 34 + 32 = 66
any of the sequence 8, 16, 24, 32, 40, ....
3 + 29 = 32 13 + 19 = 32 15 + 17 = 32
Each number is half the previous number. The series formula is a(n) = 32 *(½)n⁻¹ 32, 16, 8, 4, 2, 1, 0.5 The next three numbers in the sequence are : 0.25, 0.125, 0.0625
32