To show partial products for the multiplication problem 52 x 43, first break down each number into its place values: 52 can be expressed as 50 + 2 and 43 as 40 + 3. Next, multiply each part: 50 x 40 = 2000, 50 x 3 = 150, 2 x 40 = 80, and 2 x 3 = 6. Finally, add the partial products together: 2000 + 150 + 80 + 6 = 2236, so 52 x 43 equals 2236.
Partial products of 87 times 65 would be 80 x 60 and 80 x 5 and 7 x 60 and 7 x 5. Partial products allow for the multiplication of whole numbers.
32 and 160
The partial products for 57 times 48 are: 48 multiplied by 7, which equals 336 48 multiplied by 50, which equals 2,400 Adding these two partial products together gives a total product of 2,736.
To find the partial products for 62 x 45, you can break down the numbers into their place values. First, calculate 62 x 40 (which is 2480) and then 62 x 5 (which is 310). Adding these two partial products together gives you 2480 + 310 = 2790, which is the final result.
60 x 40 = 2400 8 x 40 = 320 60 x 3 = 180 8 x 3 = 24 68 x 43 = 2924
60 x 40 = 2400 60 x 3 = 180 8 x 40 = 320 8 x 3 = 24
20 x 40 = 800 8 x 40 = 320 3 x 20 = 60 3 x 8 = 24
how to find the partial products of a number
Partial products of 87 times 65 would be 80 x 60 and 80 x 5 and 7 x 60 and 7 x 5. Partial products allow for the multiplication of whole numbers.
700 and 210 are the answers to partial products of 77 times 30
43 x 2 = 4 x 4 x 4 x 2 = 128
80 + 24
90 and 54
32 and 160
29 x47=
The partial products for 734X29 are 6,606 and 14,680.