They are 600, 240, 80 and 32.
34 x 28 = 34 x (20 + 8) First partial product is: (30 + 4) x 8 = 240 + 32 Second partial product is: (30 + 4) x 20 = 600 + 80 Sum of partial products = total product = 600 + 240 + 80 + 32 = 952
how to find the partial products of a number
4 x 20 = 80 4 x 7 = 28 80 + 28 = 108 4 x 27 = 108
60 x 40 = 2400 8 x 40 = 320 60 x 3 = 180 8 x 3 = 24 68 x 43 = 2924
6
They are 600, 240, 80 and 32.
34 x 28 = 34 x (20 + 8) First partial product is: (30 + 4) x 8 = 240 + 32 Second partial product is: (30 + 4) x 20 = 600 + 80 Sum of partial products = total product = 600 + 240 + 80 + 32 = 952
43% of 28= 43% * 28= 0.43 * 28= 12.04
To find the partial products of 28 times 14, you would multiply each digit in the ones place of the second number (4) by each digit in the ones place of the first number (8), resulting in 32. Next, you would multiply each digit in the tens place of the second number (1) by each digit in the ones place of the first number (8), resulting in 8. Finally, you would add these two products together to get the final answer of 392.
They are: 30*20, 30*8, 2*20 and 2*8.
71
how to find the partial products of a number
4 x 20 = 80 4 x 7 = 28 80 + 28 = 108 4 x 27 = 108
60 x 40 = 2400 8 x 40 = 320 60 x 3 = 180 8 x 3 = 24 68 x 43 = 2924
the partial products for 12 and 3 30 and 6 :)
5630 is a single number and single numbers do not have partial products.