They are: 30*20, 30*8, 2*20 and 2*8.
30 x 20 = 600 30 x 8 = 240 4 x 20 = 80 4 x 8 = 32
Partial products of 87 times 65 would be 80 x 60 and 80 x 5 and 7 x 60 and 7 x 5. Partial products allow for the multiplication of whole numbers.
32 and 160
2x + 15 = 8x + 43 -6x = 28 x = -6 / 28 = -3 / 14
20 x 40 = 800 8 x 40 = 320 3 x 20 = 60 3 x 8 = 24
34 x 28 = 34 x (20 + 8) First partial product is: (30 + 4) x 8 = 240 + 32 Second partial product is: (30 + 4) x 20 = 600 + 80 Sum of partial products = total product = 600 + 240 + 80 + 32 = 952
60 x 40 = 2400 8 x 40 = 320 60 x 3 = 180 8 x 3 = 24 68 x 43 = 2924
4 x 20 = 80 4 x 7 = 28 80 + 28 = 108 4 x 27 = 108
To find the partial products of 28 times 14, you would multiply each digit in the ones place of the second number (4) by each digit in the ones place of the first number (8), resulting in 32. Next, you would multiply each digit in the tens place of the second number (1) by each digit in the ones place of the first number (8), resulting in 8. Finally, you would add these two products together to get the final answer of 392.
60 x 40 = 2400 60 x 3 = 180 8 x 40 = 320 8 x 3 = 24
They are: 30*20, 30*8, 2*20 and 2*8.
how to find the partial products of a number
43 x 28 = 1204
The two partial products of 42 X 28 are 42 X 8 (336) and 42 X 2 (84). To get the actual answer, you shift the partial product (42 X 2) one decimal space to the left and add it to the other partial product, (42 X 8). 42 X 2 = 84. Now, shift 84 one decimal space to the left. This gives you 840. 42 X 8 = 336. Now add 336 to 840 to get the final result, 1176.
30 x 20 = 600 30 x 8 = 240 4 x 20 = 80 4 x 8 = 32
Partial products of 87 times 65 would be 80 x 60 and 80 x 5 and 7 x 60 and 7 x 5. Partial products allow for the multiplication of whole numbers.