The possible values of ( N ) would depend on the specific context or constraints provided in the problem. For example, if ( N ) represents a natural number, the possible values could be any positive integer (1, 2, 3, etc.). If ( N ) is defined in a different context, such as a variable in an equation or a set of conditions, the values would vary accordingly. Without additional information, it’s difficult to provide a definitive answer.
If the principal quantum number ( n ) is 5, the possible values of the azimuthal quantum number ( l ) can range from 0 to ( n-1 ). Therefore, the possible values of ( l ) are 0, 1, 2, 3, and 4. This corresponds to the s, p, d, f, and g orbitals, respectively.
(N-1)=(4-1)= N=3 l=0,1,2,3
Since there are no lists following, the answer must be "none of them!"
[ -2n ] is positive for all negative values of 'n' .
The total number of possible outcomes in a series of events is calculated by multiplying the number of possible values for each event. This is based on the fundamental principle of counting, which states that if one event can occur in (m) ways and a subsequent event can occur in (n) ways, then the two events can occur in (m \times n) ways. For multiple events, you continue multiplying the number of options for each event together. Thus, if you have (k) events with (v_1, v_2, \ldots, v_k) possible values respectively, the total outcomes are (v_1 \times v_2 \times \ldots \times v_k).
Three different values of l are possible in the third principle or quantum level. They are: l=0, 1, and 2.
45, 90, 180
If the principal quantum number ( n ) is 5, the possible values of the azimuthal quantum number ( l ) can range from 0 to ( n-1 ). Therefore, the possible values of ( l ) are 0, 1, 2, 3, and 4. This corresponds to the s, p, d, f, and g orbitals, respectively.
(N-1)=(4-1)= N=3 l=0,1,2,3
45, 90, 180
For an electron with n=5, the possible values of l range from 0 to 4 (l=0, 1, 2, 3, 4). The value of l depends on the principal quantum number (n) according to the rule that l can be any integer value from 0 to n-1.
n = 3/2, n = 2
Since there are no lists following, the answer must be "none of them!"
4
When the principal quantum number ( n = 2 ), the angular momentum quantum number ( l ) can take on values from ( 0 ) to ( n-1 ). Therefore, for ( n = 2 ), ( l ) can be ( 0 ) (s orbital) or ( 1 ) (p orbital). This means the possible values of ( l ) are ( 0 ) and ( 1 ).
13
For the principal quantum number ( n = 2 ), the possible values of the azimuthal quantum number ( l ) are 0 and 1 (since ( l ) can take on values from 0 to ( n-1 )). For each value of ( l ), the magnetic quantum number ( m_l ) can take values from (-l) to (+l). Therefore, for ( l = 0 ), ( m_l = 0 ) (1 combination), and for ( l = 1), ( m_l ) can be (-1, 0, +1) (3 combinations). In total, there are ( 1 + 3 = 4 ) possible combinations of ( l ) and ( m_l ) for ( n = 2 ).