(N-1)=(4-1)= N=3 l=0,1,2,3
l is greater than n
All numbers between -2.5 and 3, not including -2.5.
Since there are no lists following, the answer must be "none of them!"
The question is ambiguous and the possible answers are n + 5*6 = n + 30 or (n + 5)*6
For an electron with n=5, the possible values of l range from 0 to 4 (l=0, 1, 2, 3, 4). The value of l depends on the principal quantum number (n) according to the rule that l can be any integer value from 0 to n-1.
The value of l for an orbital labeled 'g' is 4. The values of l can range from 0 to n-1, where n is the principal quantum number. So for a principal quantum number of 5 (n=5), the possible values of l can be 0, 1, 2, 3, or 4.
In the third principle level (n=3), the possible values of l can range from 0 to n-1. So for n=3, the possible values of l are 0, 1, and 2, making a total of 3 different values.
(N-1)=(4-1)= N=3 l=0,1,2,3
15
l is greater than n
I have essentially zero ability to answer that without seeing the equation. Another answer: n-1 = 3-1= 2 l=2 ml= -2,-1,0,1,2.
If l > m and m > n then l > n by the transitive property of inequality.
The magnetic quantum number (m) represents the orientation of the orbital in space and can take integer values from -l to +l, including zero. It depends on the possible values of the angular quantum number (l), which describes the shape of the orbital (s, p, d, etc). The number of possible values for m is 2l+1 for each value of l.
If n=0 that means there are no values for l
The secondary quantum number, l, represents the shape of an orbital and can have values ranging from 0 to n-1, where n is the principal quantum number. Therefore, l can have values from 0 to (n-1).
n : 2 l : 1 ml : -1, 0, or 1