If the principal quantum number ( n ) is 5, the possible values of the azimuthal quantum number ( l ) can range from 0 to ( n-1 ). Therefore, the possible values of ( l ) are 0, 1, 2, 3, and 4. This corresponds to the s, p, d, f, and g orbitals, respectively.
(N-1)=(4-1)= N=3 l=0,1,2,3
l is greater than n
All numbers between -2.5 and 3, not including -2.5.
Since there are no lists following, the answer must be "none of them!"
The question is ambiguous and the possible answers are n + 5*6 = n + 30 or (n + 5)*6
For an electron with n=5, the possible values of l range from 0 to 4 (l=0, 1, 2, 3, 4). The value of l depends on the principal quantum number (n) according to the rule that l can be any integer value from 0 to n-1.
The value of l for an orbital labeled 'g' is 4. The values of l can range from 0 to n-1, where n is the principal quantum number. So for a principal quantum number of 5 (n=5), the possible values of l can be 0, 1, 2, 3, or 4.
Three different values of l are possible in the third principle or quantum level. They are: l=0, 1, and 2.
(N-1)=(4-1)= N=3 l=0,1,2,3
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l is greater than n
I have essentially zero ability to answer that without seeing the equation. Another answer: n-1 = 3-1= 2 l=2 ml= -2,-1,0,1,2.
If l > m and m > n then l > n by the transitive property of inequality.
It depends whether you mean ml or ms.There are 4 quantum numbers, n, l, ml, msThey have long names respectively principal, azimuthal (angular momentum), magnetic and spin.n can have values 0, 1, 2, 3, 4, 5......l depends on n, and can have values, 0 to (n-1) (0 is an s orbital, 1 is a p subshell, 2 is a d subshell, 3 is a f subshell etcml can have -l to +l (sorry this font is rubbish the letter l looks like a 1) so for a d orbital, where l = 2, it can be -2, -1 0, +1, +2. Five d orbitals in all.ms can be -1/2 or +1/2 (These are the maximum of 2 electrons having opposite spin)l depends on n, and can have values, 0 to (n-1) (0 is an s orbital, 1 is a p subshell, 2 is a d subshell, 3 is a f subshell etcRead more: What_are_the_possible_values_for_the_quantum_numbers
If n=0 that means there are no values for l
The secondary quantum number, l, represents the shape of an orbital and can have values ranging from 0 to n-1, where n is the principal quantum number. Therefore, l can have values from 0 to (n-1).
n : 2 l : 1 ml : -1, 0, or 1