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If the principal quantum number ( n ) is 5, the possible values of the azimuthal quantum number ( l ) can range from 0 to ( n-1 ). Therefore, the possible values of ( l ) are 0, 1, 2, 3, and 4. This corresponds to the s, p, d, f, and g orbitals, respectively.

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How many values of l are possible when n equals 5?

For an electron with n=5, the possible values of l range from 0 to 4 (l=0, 1, 2, 3, 4). The value of l depends on the principal quantum number (n) according to the rule that l can be any integer value from 0 to n-1.


What is the value of l for orbital 'g'?

The value of l for an orbital labeled 'g' is 4. The values of l can range from 0 to n-1, where n is the principal quantum number. So for a principal quantum number of 5 (n=5), the possible values of l can be 0, 1, 2, 3, or 4.


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Three different values of l are possible in the third principle or quantum level. They are: l=0, 1, and 2.


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If l m and m n what is the relationship between the values l and n?

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If l is greater than m and m is greater than n what is the relationship between the values l and n?

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How many possible values for l and ml are there when n equals 3?

I have essentially zero ability to answer that without seeing the equation. Another answer: n-1 = 3-1= 2 l=2 ml= -2,-1,0,1,2.


If l is greater than m and m is greater than n then what is the relationship between the values of l and n?

If l > m and m > n then l > n by the transitive property of inequality.


When the magnetic quantum number m depends on the possible values of?

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What type of orbital is n equals zero and l equals one?

If n=0 that means there are no values for l


What value of secondary quantum number l?

The secondary quantum number, l, represents the shape of an orbital and can have values ranging from 0 to n-1, where n is the principal quantum number. Therefore, l can have values from 0 to (n-1).


Values of n l and ml of 2p orbital?

n : 2 l : 1 ml : -1, 0, or 1