The six consecutive integers greater than -7 are: -7, -6, -5, -4, -3, -2
The 3 consecutive odd positive integers are 7, 9 and 11.
There is no set of six consecutive integers for -4.
Since negative six is not an odd integer, there cannot be any set of odd integers starting from it.
there cannot be any nos like that.. product of 2 odd nos is odd.. sum of two even nos is even.. that multiplied by six is even too.. subtracting 2 from that also gives an even no.. let x and y be the odd integers. according to the given question xy=6(x+y)-2..here we r actually equatin an odd no and an even no.. which is wrong.. so there cant be any two consecutive odd nos that fit in the question
The six consecutive integers greater than -7 are: -7, -6, -5, -4, -3, -2
It is 53. 53 + 55 + 57 + 59 + 61 + 63 = 348
The 3 consecutive odd positive integers are 7, 9 and 11.
There is no set of six consecutive integers for -4.
Since negative six is not an odd integer, there cannot be any set of odd integers starting from it.
there cannot be any nos like that.. product of 2 odd nos is odd.. sum of two even nos is even.. that multiplied by six is even too.. subtracting 2 from that also gives an even no.. let x and y be the odd integers. according to the given question xy=6(x+y)-2..here we r actually equatin an odd no and an even no.. which is wrong.. so there cant be any two consecutive odd nos that fit in the question
45 if the smallest is a, then the numbers are a, a+2, a+4, a+6, a+8, a+10 a + (a+2) + (a+4) + (a+6) + (a+8) + (a+10) = 300 6a + 30 = 300 6a = 270 a = 45
If you mean six consecutive INTEGERS, then the answer is Yes.
1, 3, 5, 7, 9, 11 are six consecutive odd numbers whose sum is 36
25, 26, 27, 28, 29, 30
The integers are -14, -12 and -10.
Six and seven