There is no such thing as a solution for a single number!
16 = 16 is an identity, not an equation. An identity does not have solutions.
Since both positive*positive and negative*negative equal a positive number, the square root of 16 can either be +4 or -4.
x2 -y2 =16 This is an equation that describes your problem. We can write this equation as (1/16)x2 -(1/16)y2 =1 You may recognize this as the equation whose graph is a hyperbola. So there are an infinite number of solutions.
To determine the number of real solutions for the equation (4x^2 + 16x + 16 = 0), we can use the discriminant (D = b^2 - 4ac). Here, (a = 4), (b = 16), and (c = 16). Calculating the discriminant gives (D = 16^2 - 4(4)(16) = 256 - 256 = 0). Since the discriminant is zero, there is exactly one real solution to the equation.
The expression (6x^{16} - 22 + 6x) is a polynomial in (x) of degree 16. A polynomial of degree (n) can have up to (n) real solutions. Therefore, this polynomial can have up to 16 solutions, depending on the specific values of the coefficients and the nature of the roots.
16 = 16 is an identity, not an equation. An identity does not have solutions.
Since both positive*positive and negative*negative equal a positive number, the square root of 16 can either be +4 or -4.
an infinite number of solutions
x2 -y2 =16 This is an equation that describes your problem. We can write this equation as (1/16)x2 -(1/16)y2 =1 You may recognize this as the equation whose graph is a hyperbola. So there are an infinite number of solutions.
To determine the number of real solutions for the equation (4x^2 + 16x + 16 = 0), we can use the discriminant (D = b^2 - 4ac). Here, (a = 4), (b = 16), and (c = 16). Calculating the discriminant gives (D = 16^2 - 4(4)(16) = 256 - 256 = 0). Since the discriminant is zero, there is exactly one real solution to the equation.
The expression (6x^{16} - 22 + 6x) is a polynomial in (x) of degree 16. A polynomial of degree (n) can have up to (n) real solutions. Therefore, this polynomial can have up to 16 solutions, depending on the specific values of the coefficients and the nature of the roots.
The number of basic solutions in an optimization problem is determined by the number of decision variables. For a problem with n decision variables, there can be a maximum of n basic solutions.
It does not have any solutions! 14.8 is a number, not an equation, inequality or question and so has no solutions.
Equations: 3x-5y = 16 and xy = 7 Solutions: (7, 1) and (-5/3, -21/5)
There is only one solution to that equation. It's . . . . . x = -16
It is the number 16.
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