They are: 100, 105 and 110
23, 46, 69, 92, 115, 138.
23, 46, 69, 92, 115, 138
just multiply 23 by succesive whole numbers 23 46 69 92 115 138
23, 46, 69, 92, 115, 138, 161, 184, 207, 230
The first ten positive integer multiples of 115 are as follows: 115 x 1 = 115 115 x 2 = 230 115 x 3 = 345 115 x 4 = 460 115 x 5 = 575 115 x 6 = 690 115 x 7 = 805 115 x 8 = 920 115 x 9 = 1035 115 x 10 = 1150
35, 70, 115, 145, 180...
The first five multiples of 23 are: 23, 46, 69, 92, 115.
115, 230, 345 and so on.
They are: 100, 105 and 110
115, 230, 345 and so on.
A number is divisible by 115 if it is divisible by both 5 and 23, as 115 = 5 * 23. To determine if a number is divisible by 5, you check if its last digit is 0 or 5. To check if a number is divisible by 23, you can use the divisibility rule for 23, which involves subtracting four times the last digit from the rest of the number and checking if the result is divisible by 23.
77, 88, 99, 110.
They are: 23, 46, 69, 92 and 115
115, 230, 345.
115, 230, 345.
23, 46, 69, 92, 115, 138