The question is incorrect since there are 210 - 1 possible combinations.
The digit 0 can be in the combination or out. That gives 2 ways.
With each, the digit 1 can be in the combination or out - 2*2 = 22 ways.
With each, the digit 2 can be in the combination or out = 23 ways.
With each, the digit 3 can be in the combination or out = 24 ways.
etc.
So 210 ways in all except that one of them is the null combination.
Now 210 = 1024 so there are only 1023 combinations.
If, instead, you allow the digits to be used many times, there is no limit to the number of combinations.
137, 173, 317, 371, 713, 731 Six combinations can be made.
Using the combination fuction, chose three numbers from 45 numbers. The answer is 14,190.
In a 7 segment display, the symbols can be created using a selected number of segments where each segment is treated as a different element.When 1 segment is used, the possible positions are 7because it can be any of the 7 segments (7C1=7).When 2 segments are used, the number of possible combinations are 7C2=21.When 3 segments are used, the number of possible combinations are 7C3=35When 4 segments are used, the number of possible combinations are 7C4=35When 5 segments are used, the number of possible combinations are 7C5=21When 6 segments are used, the number of possible combinations are 7C6=7When 7 segments are used, the number of possible combinations are 7C7=1Adding the combinations, 7+21+35+21+7+1=127Therefore, 127 symbols can be made using a 7 segment display!
Precisely 1. For ANY number n, the number of combinations of n of those items is always 1.
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
Assuming you are using the standard English alphabet, the number of combinations you can make are: 26 x 26 = 676 combinations.
9
137, 173, 317, 371, 713, 731 Six combinations can be made.
Using the combination fuction, chose three numbers from 45 numbers. The answer is 14,190.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
Their is 25 combinations
In a 7 segment display, the symbols can be created using a selected number of segments where each segment is treated as a different element.When 1 segment is used, the possible positions are 7because it can be any of the 7 segments (7C1=7).When 2 segments are used, the number of possible combinations are 7C2=21.When 3 segments are used, the number of possible combinations are 7C3=35When 4 segments are used, the number of possible combinations are 7C4=35When 5 segments are used, the number of possible combinations are 7C5=21When 6 segments are used, the number of possible combinations are 7C6=7When 7 segments are used, the number of possible combinations are 7C7=1Adding the combinations, 7+21+35+21+7+1=127Therefore, 127 symbols can be made using a 7 segment display!
Assuming that the only permitted operation is addition, then there are 4 combinations.
Well are you trying to make a certien number ?
You can make six different combinations: 123 132 213 231 321 312. If you just need to know the number of combinations, you could find the answer without writing everything out by letting x represent the number of digits and calculating x*(x-1).
Precisely 1. For ANY number n, the number of combinations of n of those items is always 1.
Yuo can make only one combination of 30 digits using 30 digits.