The sum of the even numbers is (26 + 28 + ... + 100); The sum of the odd numbers is (25 + 27 + ... + 99) Their difference is: (26 + 28 + ... + 100) - (25 + 27 + ... + 99) = (26 - 25) + (28 - 27) + ... + (100 - 99) = 1 + 1 + ... + 1 There are (100 - 26) ÷ 2 + 1 = 38 terms above which are all 1; their sum is 38 x 1 = 38. So the difference of the sum of all even numbers and all odd numbers 25-100 is 38.
The numbers are 38, 39, and 40.
Let n be the smaller number of the two. n + (n+2) = 38 Solving, we have n = 18.
37 +1
29 & 38
40 and 2. 40-38=2 and 40+2 = 42.
The sum of the even numbers is (26 + 28 + ... + 100); The sum of the odd numbers is (25 + 27 + ... + 99) Their difference is: (26 + 28 + ... + 100) - (25 + 27 + ... + 99) = (26 - 25) + (28 - 27) + ... + (100 - 99) = 1 + 1 + ... + 1 There are (100 - 26) ÷ 2 + 1 = 38 terms above which are all 1; their sum is 38 x 1 = 38. So the difference of the sum of all even numbers and all odd numbers 25-100 is 38.
The numbers are 38 and 39.
18 and 38
18 and 38
171 - 38 = 133 so 133 + 38 sum to 171
The two prime numbers whose sum is 75 are 37 and 38. 37 is a prime number because it has only two factors: 1 and 37. 38 is not a prime number because it has more than two factors (1, 2, 19, and 38).
The sum of the four given numbers is -13.
2356 = 2 x 2 x 19 x 31 so 38 & 62 are your numbers
The numbers are 38, 39, and 40.
Let n be the smaller number of the two. n + (n+2) = 38 Solving, we have n = 18.
37 +1