The sum of the even numbers is (26 + 28 + ... + 100); The sum of the odd numbers is (25 + 27 + ... + 99) Their difference is: (26 + 28 + ... + 100) - (25 + 27 + ... + 99) = (26 - 25) + (28 - 27) + ... + (100 - 99) = 1 + 1 + ... + 1 There are (100 - 26) ÷ 2 + 1 = 38 terms above which are all 1; their sum is 38 x 1 = 38. So the difference of the sum of all even numbers and all odd numbers 25-100 is 38.
The numbers are 38, 39, and 40.
Let n be the smaller number of the two. n + (n+2) = 38 Solving, we have n = 18.
37 +1
29 & 38
40 and 2. 40-38=2 and 40+2 = 42.
Let's denote the two numbers as x and y. From the given conditions, we can write the equations x + y = 64 and x - y = 12. By solving these two equations simultaneously, we can find the values of x and y. Adding the two equations eliminates y, giving 2x = 76, so x = 38. Substituting x back into one of the equations gives y = 26. Therefore, the two numbers are 38 and 26.
The sum of the even numbers is (26 + 28 + ... + 100); The sum of the odd numbers is (25 + 27 + ... + 99) Their difference is: (26 + 28 + ... + 100) - (25 + 27 + ... + 99) = (26 - 25) + (28 - 27) + ... + (100 - 99) = 1 + 1 + ... + 1 There are (100 - 26) ÷ 2 + 1 = 38 terms above which are all 1; their sum is 38 x 1 = 38. So the difference of the sum of all even numbers and all odd numbers 25-100 is 38.
The numbers are 38 and 39.
18 and 38
18 and 38
171 - 38 = 133 so 133 + 38 sum to 171
The sum of the four given numbers is -13.
2356 = 2 x 2 x 19 x 31 so 38 & 62 are your numbers
The numbers are 38, 39, and 40.
Let n be the smaller number of the two. n + (n+2) = 38 Solving, we have n = 18.
37 +1