38; 39; 40!
The numbers are 37, 39 and 41.
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
38, 39, 40
The sum of the first 30 consecutive odd numbers is 900.
38; 39; 40!
The numbers are 37, 39 and 41.
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
There are no two consecutive whole numbers that sum to 142.With two consecutive whole numbers, one is even and the other odd, and their sum will be odd, but 142 is even.Two consecutive even numbers that sum to 142 are 70 and 72.
Let the smallest number be x. Then the others are x+1, x+2 and x+3 and x + (x+1) + (x+2) + (x+3) = 474 iff 4x = 468 iff x = 117, So the consecutive whole numbers 117, 118, 119 and 120 sum to 474.
No
38, 39, 40
No two consecutive integers have a sum of 2012.
The sum of the first 60 consecutive odd numbers is 3,600.
The sum of the first 60 consecutive odd numbers is 3,600.
the sum of first 50 consecutive odd numbers is 9801
The sum of the first 600 consecutive odd numbers is 360,000.