There are 56 of them and I am not inclined to list them all.
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Assuming that the eight numbers are all different and that none of them are zero, the number of combinations is 8C3 = 8!/(3!*5!) where n! = 1*2*3*...*n the number is 8*7*6 / (3*2*1) = 56
There are only four combinations but there are 8 permutations.
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
There are 10 choices for the first number, 9 for the second and 8 for the third. 10*9*8=720 possible combinations.
The list of 5 number combinations from the numbers 1-2-3-4-5-6-7-8 includes various groupings. For example, some combinations are: (1, 2, 3, 4, 5), (2, 3, 4, 5, 6), (3, 4, 5, 6, 7), (4, 5, 6, 7, 8), and (1, 3, 5, 7, 8). The total number of unique combinations can be calculated using combinatorial methods.