the answer is = first 2-digit number by using 48= 28,82 and in 3 digit is=282,228,822,822
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
There are twelve possible solutions using the rule you stated.
10,000 combinations.
There are 5,461,512 such combinations.
There is only 1 combination.
64
Using the eight digits, 1 - 8 ,-- There are 40,320 eight-digit permutations.-- There is 1 eight-digit combination.
A 4-digit number can range from 0000 to 9999, which includes all combinations of four digits. Since each digit can be any number from 0 to 9 (10 options), the total number of combinations is calculated as (10^4). Therefore, there are 10,000 different combinations for a 4-digit number.
216
There are 840 4-digit combinations without repeating any digit in the combinations.
To find the number of 3-digit combinations using the digits 0 to 9 with repetition allowed, we consider that each digit can be any of the 10 digits (0-9). Since there are 3 positions in the combination, the total number of combinations is calculated as (10 \times 10 \times 10), which equals 1,000. Therefore, there are 1,000 possible 3-digit combinations.
There are 5,040 combinations.