It is 2500.
There are two.
They are 2n+2
49, 51
For any integer n, the numbers 2n + 1 and 2n + 3 are consecutive odd integers.
It is 2500.
There are two.
They are 2n+2
Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.
4900
The first odd positive integers are "1" and "3" which the sum is 4.
49, 51
The sum of the integers from 1 to 100 inclusive is 5,050.
For any integer n, the numbers 2n + 1 and 2n + 3 are consecutive odd integers.
The integers are -1, 1 and 3.
you can say that 2/10 of every 10 integers is divisible by 5, so multiplying 2/10 by 100, giving you 200/1000 total integers are divisible by 5. half of all integers are odd, so divide 200/1000 by 2 is 100/1000, so you can correctly state that 100 odd integers under 1000 are divisible by 5.
Integers, odd integers, negative integers, odd negative integers, rational numbers, negative rational numbers, real numbers, negative real numbers, square roots of 1, etc.