The integers are -1, 1 and 3.
-1, 1, 3, 5
101
It is 100*(100+1)/2 = 50500.
Should be 50! Every odd integer is 1 less than the corresponding even integer and there are 50 of each in 100...
The sum of the integers from 1 to 100 inclusive is 5,050.
The first odd positive integers are "1" and "3" which the sum is 4.
4900
Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.
The integers are -1, 1 and 3.
-1, 1, 3, 5
The formula for the sum of the squares of odd integers from 1 to n is n(n + 1)(n + 2) ÷ 6. EXAMPLE : Sum of odd integer squares from 1 to 15 = 15 x 16 x 17 ÷ 6 = 680
101
The numbers are -3, -1, and 1.
The sum of all the odd numbers from 1 through 100 is 10,000
Let's talk this out and see if we can work it out. The sum of the first N odd integers means, 1+3+5+7+9+11+... Where N is how many odd numbers we're adding. Let's choose numbers for N, and see if we can find a pattern. N=1 --> 1 (sum of the first odd integer) N=2 --> 1 + 3 = 4 (sum of the first 2 odd integers) N=3 --> 1 + 3 + 5 = 9 (sum of the first 3 odd integers) N=4 --> 1 + 3 + 5 + 7 = 16 Do you notice a pattern yet? Take a look at when N = 2, what is the sum? That's right, 4! and when N = 3... the sum is 9. N = 4 the sum is 16.... I see a pattern, do you? Answer: If you don't, you'll notice that the sum of the first N odd integers is always = N2
The average of the two odd integers is 28. Therefore the two integers are 28-1 and 28+1, i.e 27 and 29.