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What are the areas of two rectangles when the rectangle 3 cm by 2x-1 cm is equal to the area of the rectangle 5 by x plus 3 cm showing work from start to finish?
The area of a rectangle is found by multiplying the length times the width.
3(2x - 1) = 6x - 3
5(x + 3) = 5x + 15
According to the text, these are equal to each other.
6x - 3 = 5x + 15
Solve for x.
x - 3 = 15
x = 18
Substitute 18 into the original dimensions.
3(36 - 1) = 105
5(18 + 3) = 105
The areas of both rectangles (3 x 35 and 5 x 21) is 105 square cm.
What else can I help you with?
Two rectangles have a perimeter of sixteen inchesName two possible areas for each rectangle?
i am doing my homework right now and I am stuck on that problem
If two rectangles have the same perimetre they must have the same area?
No, two rectangles with the same perimeter do not necessarily have the same area. The area of a rectangle is calculated as length multiplied by width, while the perimeter is the sum of all sides. For example, a rectangle with dimensions 2x5 (perimeter 14) has an area of 10, while a rectangle with dimensions 3x4 (also perimeter 14) has an area of 12. Thus, rectangles can have the same perimeter but different areas.
Finding areas of oddly shaped rectangles?
What is an "oddly shaped rectangle"? Rectangles have four sides, with two pairs of sides that are equal in length and parallel to each other, and four right angles. Anything that fits this definition is a rectangle, period. There's nothing "odd" about any of them. But the area of any rectangle can be found by multiplying the lengths of any two adjacent sides.
The areas of 2 rectangles are 15 cm squared and 60 cm squared the length of the first rectangle is 5 cm What is the width?
For the first rectangle, (L x W) = (5 x W) = 15, so W = 3 cm.The second rectangle is included in the question just to confuse you.
How many rectangles have the same area but different perimeters?
Infinitely many. Suppose the area of the rectangle is 100. We could create rectangles of different areas: 100x1 50x2 25x4 20x5 10x10 However, the side lengths need not be integers, which is why we can create infinitely many rectangles. Generally, if A is the area of the rectangle, and L, L/A are its dimensions, then the amount 2(L + (L/A)) can range from a given amount (min. occurs at L = sqrt(A), perimeter = 4sqrt(A)) to infinity.
How are rectangles related to the distributive property?
Rectangles are related to the distributive property because you can divide a rectangle into smaller rectangles. The sum of the areas of the smaller rectangles will equal the area of the larger rectangle.
Can rectangles with the same perimeter have different areas?
Yes. Say there are two rectangles, both with perimeter of 20. One of the rectangles is a 2 by 8 rectangle. The area of this rectangle is 2 x 8 which is 16. The other rectangle is a 4 by 6 rectangle. It has an area of 4 x 6 which is 24.
What is its the width of 2 rectangles that the areas are 15cm2 and 60cm2 the lengt of the first rectangle is 5cm?
I can give the width of one of the rectangles. The first rectangle of area 15 cm2 and length of 5 cm has width of 3 cm. It is impossible to know the width of the other rectangle of area 60 cm2. However, if you had said that the two rectangles were similar, then the dimensions of the second rectangle would be 10 cm X 6 cm. But you didn't say that the two rectangles were similar; so there are infinite possibilities of what the dimensions of the second rectangle might be.
Why could two students obtain different values for the calculated areas of the same rectangle?
because it was estimation, the lengths were different and the rectangles are not the same
Two rectangles have a perimeter of sixteen inchesName two possible areas for each rectangle?
i am doing my homework right now and I am stuck on that problem
If two rectangles have the same perimetre they must have the same area?
No, two rectangles with the same perimeter do not necessarily have the same area. The area of a rectangle is calculated as length multiplied by width, while the perimeter is the sum of all sides. For example, a rectangle with dimensions 2x5 (perimeter 14) has an area of 10, while a rectangle with dimensions 3x4 (also perimeter 14) has an area of 12. Thus, rectangles can have the same perimeter but different areas.
Finding areas of oddly shaped rectangles?
What is an "oddly shaped rectangle"? Rectangles have four sides, with two pairs of sides that are equal in length and parallel to each other, and four right angles. Anything that fits this definition is a rectangle, period. There's nothing "odd" about any of them. But the area of any rectangle can be found by multiplying the lengths of any two adjacent sides.
How do you work out the area of a compound shape?
wht u hve to do is to cut the shape into rectangles and then times the length and width together on each rectangle. then add up all the rectangles areas and add them alll up. ta da
Rectangles with the area of 24cm?
In order to get a rectangle with an area of 24 centimeters, the length and width multiplied need to equal 24. On top of that, length and width may not be equal, or the shape would be a square instead of a rectangle. Examples of rectangles with 24cm areas: 1x24 cm 2x12 cm 3x8 cm 4x6 cm
What is the relationship for perimeter and area for rectangle?
There is no relationship between the perimeter and area of a rectangle. Knowing the perimeter, it's not possible to find the area. If you pick a number for the perimeter, there are an infinite number of rectangles with different areas that all have that perimeter. Knowing the area, it's not possible to find the perimeter. If you pick a number for the area, there are an infinite number of rectangles with different perimeters that all have that area.
The areas of 2 rectangles are 15 cm squared and 60 cm squared the length of the first rectangle is 5 cm What is the width?
For the first rectangle, (L x W) = (5 x W) = 15, so W = 3 cm.The second rectangle is included in the question just to confuse you.
How many rectangles have the same area but different perimeters?
Infinitely many. Suppose the area of the rectangle is 100. We could create rectangles of different areas: 100x1 50x2 25x4 20x5 10x10 However, the side lengths need not be integers, which is why we can create infinitely many rectangles. Generally, if A is the area of the rectangle, and L, L/A are its dimensions, then the amount 2(L + (L/A)) can range from a given amount (min. occurs at L = sqrt(A), perimeter = 4sqrt(A)) to infinity.
