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It is impossible to be sure but it is likely that the centre is (2, 9) and the radius is 5 units.
Center of circle: (6, 8) Radius of circle: 3
I think it is center: (-4, 3) ; radius: 2 Apex:)
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
depends on the equation.
cxbdfbdb
Center of circle: (6, 8) Radius of circle: 3
I think it is center: (-4, 3) ; radius: 2 Apex:)
Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
depends on the equation.
The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100
this is impossible
cxbdfbdb
The equation of the circle is: x^2 + y^2 = 81
Centre of the circle: (3, 8) Radius of the circle: 2 Cartesian equation of the circle: (x-3)^2 + (y-8)^2 = 4
To determine the center and radius of a circle described by an equation in the form "(x-h)^2 + (y-k)^2 = r^2", we need to rewrite the given equation in that form. The equation (x-7)^2 + (y-6)^2 = 2100 is already in that form. Therefore, the center of the circle is at the point (7, 6) and the radius is the square root of 2100.
x2 + y2 = 64