The 3 cube-roots of 8i are:
Think of 8i in polar form as 8∠90°. A number raised to a power (in this case 1/3) is the magnitude raised to the power and the angle is the angle times the power.
So 8 raised to 1/3 power is 2. And 90° * (1/3) = 30°. To find the angles of the other 2 cube-roots, find equivalent angles (add 360° & 720°). So you have 450°/3 = 150° and 810°/3 = 270°.
So the three roots: 2∠30°, 2∠150° & 2∠270°. Which are the three answers, above (in rectangular coordinates)
8 - 8i
8i
It is just 11+8i.
-5-7=-126i-8i=-2i-12-2i is your final answer
It's 8 sqrt(2) at an angle of 135° .
8 - 8i
8i
It is just 11+8i.
-5-7=-126i-8i=-2i-12-2i is your final answer
8i
It's 8 sqrt(2) at an angle of 135° .
(2 + 4i) - (7 + 4i) = -5 2 + 4i - 7 + 4i = -5 + 8i
8i and -8i both satisfy this: (8i)² = (8²)(i²) = (64)(-1) = -64, and (-8i)² = (-8²)(i²) = (64)(-1) = -64
10 + 6i and 7 + 2i = 10 + 6i + 7 + 2i = 17 + 8i
4i(-2 -3i) = 4i×-2 - 4i×-3i = -8i -12i² = -8i + 12 = 12 -8i → the conjugate is 12 + 8i
The i in Oracle 8i and Oracle 9i stands for INTERNET....The i in Oracle 8i and Oracle 9i stands for INTERNET....The i in Oracle 8i and Oracle 9i stands for INTERNET....The i in Oracle 8i and Oracle 9i stands for INTERNET....
it is having more advantages than 8i