10 + 6i and 7 + 2i = 10 + 6i + 7 + 2i = 17 + 8i
(-2 + 3i) + (-1 - 2i) = -2 + 3i - 1 - 2i = -2 - 1 + 3i - 2i = -3 + i
Not necessarily, take for example the equation x^2=5-12i. Then, 3-2i satisfies the equation. However, 3+2i does not because (3+2i)^2 = 5+12i.
-8i
36.64
This is calculated as follows: (2i)2 = 2i x 2i = 4i2 = 4(-1) = -4.
1.75 + 1.75i7i/2 + 2i = 3.5i + 2i = 5.5i
It is 2I + 1. The coefficient is put before the variable.
It is 3 minus 2i
It is 3/13 - 2/13*i
The four roots are:1 + 2i, 1 - 2i, 3i and -3i.
To solve this type of problem, multiply both the numerator and denominator by the conjugate of the denominator. (2 - 4i) / (4 + 2i) = (2 - 4i)(4 - 2i) / (4 + 2i)(4 - 2i) then expand all the terms, and simplify. = (8 - 20i + 8i2) / (16 - 4i2) = (8 - 20i - 8) / (16 + 4) = -20i / 20 = -i Which in the required answer format becomes, 0 + i.
(-2 + 3i) + (-1 - 2i) = -2 + 3i - 1 - 2i = -2 - 1 + 3i - 2i = -3 + i
2H+ + SO42- + Ca2+ + 2I- CaSO4 + 2H+ + 2I-
-5-7=-126i-8i=-2i-12-2i is your final answer
2i
Its equivalent to any 3 year or above Indian degree from a recognized university with an aggregate of about 58% - 2i
Not necessarily, take for example the equation x^2=5-12i. Then, 3-2i satisfies the equation. However, 3+2i does not because (3+2i)^2 = 5+12i.