8
It's 8 sqrt(2) at an angle of 135° .
8i and -8i both satisfy this: (8i)² = (8²)(i²) = (64)(-1) = -64, and (-8i)² = (-8²)(i²) = (64)(-1) = -64
Numbers of the form a + ib (where i = -11/2; a and b are real numbers) are called complex numbers.For any two complex numbers (a+ib) and (c+id):Addition:(a+ib) + (c+id) = (a+c) + i(b+d)So, -8i-7i = (-8-7)i = -15i
12
It would be 8 minus 9i or 8-9i
8
-6i-8
The conjugate of -8-4i is -8+4i. It is obtained by changing the sign of the imaginary part of the complex number.
It's 8 sqrt(2) at an angle of 135° .
8i and -8i both satisfy this: (8i)² = (8²)(i²) = (64)(-1) = -64, and (-8i)² = (-8²)(i²) = (64)(-1) = -64
Numbers of the form a + ib (where i = -11/2; a and b are real numbers) are called complex numbers.For any two complex numbers (a+ib) and (c+id):Addition:(a+ib) + (c+id) = (a+c) + i(b+d)So, -8i-7i = (-8-7)i = -15i
Since you didn't show an operator, we'll use: 1. 8-6i 2. 8+6i 3. 8 times 6i = 48i The complex conjugates are: 1. 8+6i 2. 8-6i 3. -48i
No.The roots are the complex conjugate pair 5 ± 2.4495iwhere i is the imaginary square root of -1.
12
113
If you mean 8i, i might be any variable, but it may also stand for the imaginary unit, sometimes defined as the square root of minus 1. In that case, 8i is 8 times the square root of minus 1.If you mean 8i, i might be any variable, but it may also stand for the imaginary unit, sometimes defined as the square root of minus 1. In that case, 8i is 8 times the square root of minus 1.If you mean 8i, i might be any variable, but it may also stand for the imaginary unit, sometimes defined as the square root of minus 1. In that case, 8i is 8 times the square root of minus 1.If you mean 8i, i might be any variable, but it may also stand for the imaginary unit, sometimes defined as the square root of minus 1. In that case, 8i is 8 times the square root of minus 1.