8
It's 8 sqrt(2) at an angle of 135° .
8i and -8i both satisfy this: (8i)² = (8²)(i²) = (64)(-1) = -64, and (-8i)² = (-8²)(i²) = (64)(-1) = -64
Numbers of the form a + ib (where i = -11/2; a and b are real numbers) are called complex numbers.For any two complex numbers (a+ib) and (c+id):Addition:(a+ib) + (c+id) = (a+c) + i(b+d)So, -8i-7i = (-8-7)i = -15i
12
It would be 8 minus 9i or 8-9i
8
-6i-8
The conjugate of -8-4i is -8+4i. It is obtained by changing the sign of the imaginary part of the complex number.
Oh, dude, the complex conjugate of 8 + 6i is just flipping the sign of the imaginary part, so it's 8 - 6i. It's like changing your mood from happy to grumpy, but in the world of math. So yeah, that's the deal with complex conjugates.
11
It's 8 sqrt(2) at an angle of 135° .
8i and -8i both satisfy this: (8i)² = (8²)(i²) = (64)(-1) = -64, and (-8i)² = (-8²)(i²) = (64)(-1) = -64
Numbers of the form a + ib (where i = -11/2; a and b are real numbers) are called complex numbers.For any two complex numbers (a+ib) and (c+id):Addition:(a+ib) + (c+id) = (a+c) + i(b+d)So, -8i-7i = (-8-7)i = -15i
No.The roots are the complex conjugate pair 5 ± 2.4495iwhere i is the imaginary square root of -1.
12
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