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Because the diagonals in a square are at right angles to one another!
The diagonals of a square bisect each other at 90 degrees
Yes. Think of a normal square. Now place an X in the centre of it. An X is two diagonals. When the X is placed in the square, the endpoints go from one corner to another. Therefore, a square has two diagonals.
The diagonals of a square meet at the center of the square, which is also the point of symmetry. At this intersection, the diagonals bisect each other at right angles, dividing the square into four equal triangles. This point is equidistant from all four vertices of the square.
It could be a square, but consider the following congruent & perpendicular 'diagonals of a quadrilateral (you will have to connect the endpoints of the diagonals, yourself, as it cannot be drawn in text): . _|___ . | . | . | If the two diagonals, also bisect each other, then it's a square, otherwise it is not.
It has 2 Diagonals!!!
Sure, a square is a rectangle and the diagonals of a square are perpendicular.
The diagonals of a square are perpendicular whereas the diagonals of a rectangle are not perpendicular.
Because the diagonals in a square are at right angles to one another!
The diagonals of a square are always perpendicular.
Yes the diagonals of a square are always congruent. Their length is a*root 2 where a is the side of the square.
The diagonals of a square (which always bisect each other) are the same length.
The diagonals of a square bisect each other at 90 degrees
No but the diagonals of a square intersect at right angles
Yes. Think of a normal square. Now place an X in the centre of it. An X is two diagonals. When the X is placed in the square, the endpoints go from one corner to another. Therefore, a square has two diagonals.
The diagonals of a square are perpendicular whereas the diagonals of a rectangle are not perpendicular.
A square has only to diagonals and either one will divide it in half.