ask them questions and they will tell you answers
The number of ways to arrange six students in a lunch line can be calculated using the factorial of the number of students. Specifically, this is 6! (6 factorial), which equals 6 × 5 × 4 × 3 × 2 × 1 = 720. Therefore, there are 720 different ways to arrange six students in a lunch line.
24
There are 30 ways of selecting the first student leaving 29 ways to select the second for a total of 30 X 29 = 870 ways
6! = 6 factorial = 1x2x3x4x5x6 = 720
To determine the number of different committees that can be formed with 4 teachers from 6 and 4 students from 49, we use combinations. The number of ways to choose 4 teachers from 6 is given by ( \binom{6}{4} ), and the number of ways to choose 4 students from 49 is ( \binom{49}{4} ). Thus, the total number of different committees is ( \binom{6}{4} \times \binom{49}{4} ). Calculating this gives ( 15 \times 194580 = 2918700 ) different committees.
the proper pronounciation is with a K sound Keltic, "sell-tick" is Boston being rebellious
Combination; number of ways = 21
53,130 ways.
6,375,600
There are 11880 ways.
Rebellious: deliberately disobeying someone in authority. Rebellious attitude: always wanting to go "against the grain" and be different from everyone else, and NOT wanting to do what is expected. Rock musicians are often thought of as rebellious. Rebellious also refers to citizens. The revolutionary war was a result of the colonists rebelling against King George's taxation without representation.
a.6 different waysc.12 different waysb.10 different wayd.15 different ways
333
The number of ways to arrange six students in a lunch line can be calculated using the factorial of the number of students. Specifically, this is 6! (6 factorial), which equals 6 × 5 × 4 × 3 × 2 × 1 = 720. Therefore, there are 720 different ways to arrange six students in a lunch line.
24
There are 10 different sets of teachers which can be combined with 4 different sets of students, so 40 possible committees.
Since there are 5 different prizes, and assuming a pupil can get only one prize the answer is25P5 = 6,375,600 ways.