Let one side be (x+3) and the other side be x:
area = 2(perimeter)
(x+3)*x = 2*2(x+3+x)
x2+3x = 4x+12+4x
x2+3x-8x-12 = 0
x2-5x-12 = 0
Solving the above equation using the quadratic equation formula and a calculator works out to 2 d.p. as:
x = -1.77 or x = 6.77 it must be the latter as dimensions can't be negative.
Therefore the dimensions are 6.77 cm and 9.77 cm
Yes, the perimeter of a rectangle can be larger than its area. For example, consider a rectangle with dimensions 1 unit by 1 unit, which has a perimeter of 4 units and an area of 1 square unit. As the rectangle's dimensions change, especially when one dimension is much larger than the other, the perimeter can exceed the area even more significantly.
It is not possible to answer the question because you have not defined what 32 measures: is it the area of the rectangle, its perimeter, its diagonal or some other property?
In the case of a rectangle, you would maximize the area given the perimeter by making the dimensions equal. In other words, you would make the rectangle into a square. However, to truly maximize the area, you would make the perimeter a perfect circle.
One dimension of a rectangle is its length, which is the longer side of the rectangle. The other dimension is its width, which is the shorter side. Together, these dimensions define the size and shape of the rectangle.
The length of a rectangle is one of its two dimensions, with the other being its width. If the rectangle is specified as having a length of 12 meters, then that is the measurement you are looking for. If you meant to ask about a rectangle with a perimeter or area involving 12 meters, please clarify for a more specific answer.
Yes, the perimeter of a rectangle can be larger than its area. For example, consider a rectangle with dimensions 1 unit by 1 unit, which has a perimeter of 4 units and an area of 1 square unit. As the rectangle's dimensions change, especially when one dimension is much larger than the other, the perimeter can exceed the area even more significantly.
The dimensions work out as length = 9 and width = 5
It is not possible to answer the question because you have not defined what 32 measures: is it the area of the rectangle, its perimeter, its diagonal or some other property?
In the case of a rectangle, you would maximize the area given the perimeter by making the dimensions equal. In other words, you would make the rectangle into a square. However, to truly maximize the area, you would make the perimeter a perfect circle.
One dimension of a rectangle is its length, which is the longer side of the rectangle. The other dimension is its width, which is the shorter side. Together, these dimensions define the size and shape of the rectangle.
Your question cannot be answered. An area of 14 acres is equivalent to 609,840 square feet, but a rectangle with that area could be 609,840 feet by 1 foot, or it could be 1089 feet by 560 feet, or many other possible dimensions, each of which would have a different perimeter.
To find the perimeter of a shape with an area of 480 square feet, you first need to know the shape's dimensions. For example, if you consider a rectangle, the area can be calculated as length multiplied by width (A = length × width). If you take a rectangle with dimensions of 20 feet by 24 feet, the perimeter would be 2(length + width) = 2(20 + 24) = 88 feet. Other shapes will yield different perimeters for the same area depending on their dimensions.
The length of a rectangle is one of its two dimensions, with the other being its width. If the rectangle is specified as having a length of 12 meters, then that is the measurement you are looking for. If you meant to ask about a rectangle with a perimeter or area involving 12 meters, please clarify for a more specific answer.
A rectangle with a perimeter of 10 units has a total distance around its edges equal to 10 units. The perimeter ( P ) of a rectangle is calculated using the formula ( P = 2(l + w) ), where ( l ) is the length and ( w ) is the width. Therefore, ( l + w = 5 ). Possible dimensions for such a rectangle could be ( (1, 4) ), ( (2, 3) ), or any other pair of positive numbers that sum to 5.
156 It is impossible to calculate the area of a rectangle from its perimeter if no other dimension is known. The area of a rectangle is the product of its length and width, and the perimeter is twice the sum of its length and width.
No. The length is the measurement of the distance from the bottom to the top of the rectangle, or from one side to the other side. The perimeter is the distance all the way around the rectangle.
To find a shape with a perimeter of 30 feet and an area of 35 square feet, we can consider a rectangle. If we denote the length as ( l ) and the width as ( w ), we have the equations ( 2l + 2w = 30 ) for the perimeter and ( l \times w = 35 ) for the area. Solving these equations, we can find specific dimensions, but there are multiple combinations that could satisfy these conditions, such as a rectangle or other shapes. However, achieving both the exact area and perimeter might require specific dimensions that may not correspond to a simple geometric figure.