The expression n(n - 1) represents a quadratic sequence. To find the first four terms, we can substitute n = 1, 2, 3, and 4.
Thus, the first four terms are 0, 2, 6, and 12.
The first five terms of the sequence defined by (4n) can be found by substituting (n) with the integers 1 through 5. Thus, the terms are: For (n = 1): (4 \times 1 = 4) For (n = 2): (4 \times 2 = 8) For (n = 3): (4 \times 3 = 12) For (n = 4): (4 \times 4 = 16) For (n = 5): (4 \times 5 = 20) So, the first five terms are 4, 8, 12, 16, and 20.
The given geometric sequence is 1, 4, 16, where the first term ( a = 1 ) and the common ratio ( r = 4 ). To find the sum of the first six terms, we calculate the sixth term: ( a_6 = a \cdot r^{5} = 1 \cdot 4^5 = 1024 ). The sum of the first ( n ) terms of a geometric sequence is given by the formula ( S_n = a \frac{r^n - 1}{r - 1} ). Thus, the sum of the first six terms is ( S_6 = 1 \cdot \frac{4^6 - 1}{4 - 1} = \frac{4096 - 1}{3} = \frac{4095}{3} = 1365 ).
As whole number integers? 4(1) + 1 = 5 ------ 4(2) + 1 = 9 ----- 4(3) + 1 = 13 -------
The expression "n plus 3" can be represented as ( n + 3 ). To find the first five terms, we can substitute the values ( n = 1, 2, 3, 4, ) and ( 5 ) into the expression. The first five terms are: ( 1 + 3 = 4 ) ( 2 + 3 = 5 ) ( 3 + 3 = 6 ) ( 4 + 3 = 7 ) ( 5 + 3 = 8 ) Thus, the first five terms are 4, 5, 6, 7, and 8.
This is a Fibonacci sequence where the first two terms are known as 'seed values' and successive terms are the sum of the two previous terms. 4 = 3 + 1 7 = 4 + 3 11 = 7 + 4 18 = 11 + 7.
The first five terms of the sequence defined by (4n) can be found by substituting (n) with the integers 1 through 5. Thus, the terms are: For (n = 1): (4 \times 1 = 4) For (n = 2): (4 \times 2 = 8) For (n = 3): (4 \times 3 = 12) For (n = 4): (4 \times 4 = 16) For (n = 5): (4 \times 5 = 20) So, the first five terms are 4, 8, 12, 16, and 20.
The given geometric sequence is 1, 4, 16, where the first term ( a = 1 ) and the common ratio ( r = 4 ). To find the sum of the first six terms, we calculate the sixth term: ( a_6 = a \cdot r^{5} = 1 \cdot 4^5 = 1024 ). The sum of the first ( n ) terms of a geometric sequence is given by the formula ( S_n = a \frac{r^n - 1}{r - 1} ). Thus, the sum of the first six terms is ( S_6 = 1 \cdot \frac{4^6 - 1}{4 - 1} = \frac{4096 - 1}{3} = \frac{4095}{3} = 1365 ).
As whole number integers? 4(1) + 1 = 5 ------ 4(2) + 1 = 9 ----- 4(3) + 1 = 13 -------
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The expression "n plus 3" can be represented as ( n + 3 ). To find the first five terms, we can substitute the values ( n = 1, 2, 3, 4, ) and ( 5 ) into the expression. The first five terms are: ( 1 + 3 = 4 ) ( 2 + 3 = 5 ) ( 3 + 3 = 6 ) ( 4 + 3 = 7 ) ( 5 + 3 = 8 ) Thus, the first five terms are 4, 5, 6, 7, and 8.
The nth term of the series is [ 4/2(n-1) ].
Yes, 1/4 is in its lowest terms
1/4 is already in its lowest terms
This is a Fibonacci sequence where the first two terms are known as 'seed values' and successive terms are the sum of the two previous terms. 4 = 3 + 1 7 = 4 + 3 11 = 7 + 4 18 = 11 + 7.
The expression ( k + 1 + k + 4 ) can be simplified by combining like terms. First, combine the ( k ) terms: ( k + k = 2k ). Then, combine the constant terms: ( 1 + 4 = 5 ). Therefore, the simplified expression is ( 2k + 5 ).
To find the first 5 terms, plug 1, 2, 3, 4 and 5 in for n:3*1-3 = 03*2-3 = 33*3-3 = 63*4-3 = 93*5-3 = 12The first five terms are 0, 3, 6, 9 and 12.
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