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The expression n(n - 1) represents a quadratic sequence. To find the first four terms, we can substitute n = 1, 2, 3, and 4.

  • For n = 1: 1(1 - 1) = 0
  • For n = 2: 2(2 - 1) = 2
  • For n = 3: 3(3 - 1) = 6
  • For n = 4: 4(4 - 1) = 12

Thus, the first four terms are 0, 2, 6, and 12.

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What is the sum of the first six terms of the geometric sequence 1 4 16?

The given geometric sequence is 1, 4, 16, where the first term ( a = 1 ) and the common ratio ( r = 4 ). To find the sum of the first six terms, we calculate the sixth term: ( a_6 = a \cdot r^{5} = 1 \cdot 4^5 = 1024 ). The sum of the first ( n ) terms of a geometric sequence is given by the formula ( S_n = a \frac{r^n - 1}{r - 1} ). Thus, the sum of the first six terms is ( S_6 = 1 \cdot \frac{4^6 - 1}{4 - 1} = \frac{4096 - 1}{3} = \frac{4095}{3} = 1365 ).


What are the first 3 terms for 4n plus 1?

As whole number integers? 4(1) + 1 = 5 ------ 4(2) + 1 = 9 ----- 4(3) + 1 = 13 -------


What is the rule to this pattern 1 3 4 7 11 18?

This is a Fibonacci sequence where the first two terms are known as 'seed values' and successive terms are the sum of the two previous terms. 4 = 3 + 1 7 = 4 + 3 11 = 7 + 4 18 = 11 + 7.


What is k plus 1 plus k plus 4 simplified?

The expression ( k + 1 + k + 4 ) can be simplified by combining like terms. First, combine the ( k ) terms: ( k + k = 2k ). Then, combine the constant terms: ( 1 + 4 = 5 ). Therefore, the simplified expression is ( 2k + 5 ).


What is first term of a geometric series is 3 and the sum of the first term and the second term is 15 What is the sum of the first six terms?

In a geometric series, if the first term ( a ) is 3 and the sum of the first and second terms is 15, we can denote the common ratio as ( r ). Therefore, we have ( 3 + 3r = 15 ), which simplifies to ( 3r = 12 ) or ( r = 4 ). The sum of the first six terms can be calculated using the formula ( S_n = a \frac{1 - r^n}{1 - r} ). Substituting ( a = 3 ), ( r = 4 ), and ( n = 6 ), we get ( S_6 = 3 \frac{1 - 4^6}{1 - 4} = 3 \frac{1 - 4096}{-3} = 4095 ).