The expression n(n - 1) represents a quadratic sequence. To find the first four terms, we can substitute n = 1, 2, 3, and 4.
Thus, the first four terms are 0, 2, 6, and 12.
As whole number integers? 4(1) + 1 = 5 ------ 4(2) + 1 = 9 ----- 4(3) + 1 = 13 -------
This is a Fibonacci sequence where the first two terms are known as 'seed values' and successive terms are the sum of the two previous terms. 4 = 3 + 1 7 = 4 + 3 11 = 7 + 4 18 = 11 + 7.
2/4 = 1/2
3/24 = 1/8 in its lowest terms
To simplify the expression ((1x^2 - 2x + 4) + (2x + 1) - (x^2 + 5)), first combine like terms. The (x^2) terms give (1x^2 - 1x^2 = 0). The (x) terms yield (-2x + 2x = 0), and the constant terms combine to (4 + 1 - 5 = 0). Thus, the simplified expression is (0).
As whole number integers? 4(1) + 1 = 5 ------ 4(2) + 1 = 9 ----- 4(3) + 1 = 13 -------
go nn
Yes, 1/4 is in its lowest terms
1/4 is already in its lowest terms
The nth term of the series is [ 4/2(n-1) ].
This is a Fibonacci sequence where the first two terms are known as 'seed values' and successive terms are the sum of the two previous terms. 4 = 3 + 1 7 = 4 + 3 11 = 7 + 4 18 = 11 + 7.
To find the first 5 terms, plug 1, 2, 3, 4 and 5 in for n:3*1-3 = 03*2-3 = 33*3-3 = 63*4-3 = 93*5-3 = 12The first five terms are 0, 3, 6, 9 and 12.
5
5
12
4/28 is 1/7 in lowest terms.
The first five positive integer terms for 3n + 4 are: 1 = 7 2 = 10 3 = 13 4 = 16 5 = 19