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To find the first 5 terms, plug 1, 2, 3, 4 and 5 in for n:

3*1-3 = 0

3*2-3 = 3

3*3-3 = 6

3*4-3 = 9

3*5-3 = 12

The first five terms are 0, 3, 6, 9 and 12.

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2n - 1

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1 7 13 19

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Q: What are the first 5 terms in the sequence 3n-3?
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What is the sum of first six terms of a sequence whose nth term is 8 - n?

nth term is 8 - n. an = 8 - n, so the sequence is {7, 6, 5, 4, 3, 2,...} (this is a decreasing sequence since the successor term is smaller than the nth term). So, the sum of first six terms of the sequence is 27.


Find the quadratic sequences nth term for these 4 sequences which are separated by the letter i iii 7 10 15 22 21 42 iii 2 9 18 29 42 57 iii 4 15 32 55 85 119 iii 5 12 27 50 81 120?

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What is the sum of first six terms of a sequence whose nth term is 4n-2?

The first 6 terms would be when n is 1, 2, 3, 4, 5, and 6. And since the nth term is 3 - 4n, you would simply substitute the first six numbers for n:* n = 1; 3 - 4(1); 3 - 4; -1 * n = 2; 3 - 4(2); 3 - 8; -5 * n = 3; 3 - 4(3); 3 - 12; -9 * n = 4; 3 - 4(4); 3 - 16; -13 * n = 5; 3 - 4(5); 3 - 20; -17 * n = 6; 3 - 4(6); 3 - 24; -21 -1, -5, -9, -13, -17, -21

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