Starting from 1, your get:
[4n + 5] = 9, 13, 17, 21, 25
Basically you find the first one and add 4 each time.
20n2+6n-2 (4n + 2)(5n -1) This problem can be solved by FOILing. First, multiply the first terms to get 20n2 Next, multiply the outside terms to get -4n. Multiplication of the inside terms results in 10n. Combining -4n and 10n (they are like terms) is 6n. Then, multiply the last terms, to get -2. Combining these answers into one equation gives the answer of 20n2+6n-2.
4n + 1 = 12 + 5n First, let's get all n terms on one side and all non-n terms on the other side. Start off by subtracting 4n from each side. 1 = 12 + n Now subtract 12 from each side. -11 = n
The first five terms of the sequence defined by (4n) can be found by substituting (n) with the integers 1 through 5. Thus, the terms are: For (n = 1): (4 \times 1 = 4) For (n = 2): (4 \times 2 = 8) For (n = 3): (4 \times 3 = 12) For (n = 4): (4 \times 4 = 16) For (n = 5): (4 \times 5 = 20) So, the first five terms are 4, 8, 12, 16, and 20.
4, 8, 12
3 7 11
5
the first 4 terms of the sequence which has the nth term is a sequence of numbers that that goe together eg. 8,12,16,20,24 the nth term would be 4n+4
The sequence 4n + 7 represents a linear sequence where n is the position in the sequence. To find the first five terms, substitute n with 1, 2, 3, 4, and 5 respectively. Thus, the first five terms are 11, 15, 19, 23, and 27.
20n2+6n-2 (4n + 2)(5n -1) This problem can be solved by FOILing. First, multiply the first terms to get 20n2 Next, multiply the outside terms to get -4n. Multiplication of the inside terms results in 10n. Combining -4n and 10n (they are like terms) is 6n. Then, multiply the last terms, to get -2. Combining these answers into one equation gives the answer of 20n2+6n-2.
4
4n + 1 = 12 + 5n First, let's get all n terms on one side and all non-n terms on the other side. Start off by subtracting 4n from each side. 1 = 12 + n Now subtract 12 from each side. -11 = n
5
The first five terms of the sequence defined by (4n) can be found by substituting (n) with the integers 1 through 5. Thus, the terms are: For (n = 1): (4 \times 1 = 4) For (n = 2): (4 \times 2 = 8) For (n = 3): (4 \times 3 = 12) For (n = 4): (4 \times 4 = 16) For (n = 5): (4 \times 5 = 20) So, the first five terms are 4, 8, 12, 16, and 20.
8m + (4n - 6m) + 9n =8m + 4n - 6m + 9n =(8m - 6m) + (4n + 9n) =2m + 13n
4, 8, 12
3 7 11
yes because the + and the - are two terms. hope this helps :3