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Q: What are the first four terms of the sequence an 4n -1?

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the first 4 terms of the sequence which has the nth term is a sequence of numbers that that goe together eg. 8,12,16,20,24 the nth term would be 4n+4

Starting from 1, your get: [4n + 5] = 9, 13, 17, 21, 25 Basically you find the first one and add 4 each time.

4, 8, 12

Unless otherwise stated any series/sequence starts with n = 1 Then the first three terms are when n = 1, n= 2 and n = 3 and the series formula 4n - 2 gives the related results, 2, 6 and 10.

3 7 11

You need an equation for the nth term of the sequence, or some other means of identifying the sequence. In general, they will be a+n, a+2n, a+3n and a+4n although some go for a, a+n, a+2n and a+3n.

20n2+6n-2 (4n + 2)(5n -1) This problem can be solved by FOILing. First, multiply the first terms to get 20n2 Next, multiply the outside terms to get -4n. Multiplication of the inside terms results in 10n. Combining -4n and 10n (they are like terms) is 6n. Then, multiply the last terms, to get -2. Combining these answers into one equation gives the answer of 20n2+6n-2.

To find the equation of a sequence, you first have to look at the differences between the numbers. In this case the differences are 4, and 4. Thus the equation begins 4n. The sequence minus 4n is: 3, 3, 3 Thus the equation in its entirety is that the value of the term in position n is 4n+3

4N is four times n...pretty simple.

They are -2, 2, 6, 10 and 14.

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