product = 6 first three positive counting numbers = 1, 2, 3product of the first three positive counting numbers:1 x 2 x 3 = 6
positive
The first ten positive numbers total 55.
Six.
The sum of the first three even positive integers is 2 + 4 + 6 = 12.
The sum of the first six positive numbers (1 to 6) is 21.
product = 6 first three positive counting numbers = 1, 2, 3product of the first three positive counting numbers:1 x 2 x 3 = 6
2 4 6 8
1 2 3 4 5 6 and 7 are the first 7 positive #s
positive
2 + 4 + 6 + 8 + 10 + 12 = 42
The first ten positive numbers total 55.
The sum of the first 1,000,000 positive even numbers is: 2 + 4 + 6 + 8 + ... + 2,000,000 The sum of the first 1,000,000 positive odd integers is: 1 + 3 + 5 + 7 + ... + 1,999,999 The difference between the two is: (2-1) + (4-3) + (6-5) + (8-7) + ... + (2,000,000-1,999,999). This is the same as: 1 + 1 + 1 + 1 + ... + 1. Well how many 1's are there? 1,000,000. So the difference is 1,000,000. Note that if the question asked for the difference between the sum of the first 1,000 positive even numbers and the sum of the first 1,000 positive odd numbers, the answer would be 1,000. The first n even numbers and odd numbers? n.
The first 10 positive whole numbers are: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10.The even numbers among those are 2, 4, 6, 8, 10.So there are 5 ways of choosing an even number from among the first 10 positive whole numbers.
Six.
the first positive even numbers are 2,4,6,8,10
The sum of the first 30 positive even numbers is 930.