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How many combinations of 6 numbers are there in 44 numbers?
Just use combinations formula. nCr, where n=44, r=6. Plug it into the calculator or use the formula, nCr = n!/[r!(n-r)!] And you should get 7059052 as the number of combinations.
If using numbers 1 thru 49 how many 6 digit combinations can be made?
Using the formula n!/r!(n-r)! where n is the number of possible numbers and r is the number of numbers chosen, there are 13983816 combinations of six numbers between 1 and 49 inclusive.
How many 6-number combinations are there for numbers 1-39?
To calculate the number of 6-number combinations from a pool of numbers 1-39, we can use the combination formula, which is nCr = n! / (r!(n-r)!). In this case, n = 39 (total numbers) and r = 6 (numbers chosen). Plugging these values into the formula, we get 39C6 = 39! / (6!(39-6)!) = 3,262,623 unique combinations.
What are the 6 combination numbers there in 55 numbers?
I am not stupid enough to try and list them since there are 55*54*53*52*51*50/(6*5*4*3*2*1) = 28,989,675 combinations. nPr=permutation while nCr=combination. The question is how many combination of 6 are there in 55 numbers. So the answer should be based on the formula: nPr = n!/(n-r)! where ! is factorial and nCr = nPr/r! = n!/{(n-r)*r!} ; So using the formula should look likr this 55C6 = 55!/{(55-6)!*6!} = 55!/(49!*6!) = 28,989,675
Can rational numbers r?
No, rational numbers cannot r.
