Well, honey, if you have 7 numbers and you're picking 6 of them, there are 7 ways to pick the first number, 6 ways to pick the second number, 5 ways for the third number, and so on until you've picked all 6 numbers. So, the number of combinations would be 7 x 6 x 5 x 4 x 3 x 2, which is 5040. It's like picking out outfits for the week, just with numbers instead of clothes.
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The number of combinations of choosing 6 numbers from a set of 7 numbers can be calculated using the formula for combinations, which is nCr = n! / (r!(n-r)!). In this case, n = 7 and r = 6. Plugging these values into the formula, we get 7! / (6!(7-6)!) = 7 ways to choose 6 numbers from a set of 7 numbers.
Oh, dude, this is like one of those math problems that make you question your entire existence. So, if you have 7 numbers and you're picking 6, you'd have 7 choose 6 possible combinations, which is just 7. I mean, who needs all those extra combinations anyway, right?
There are 7 combinations. Each combination excludes a different one of the seven numbers.
7
There are 7C4 = 7!/(4!*3!) = 7*6*5/(3*2*1) = 35 combinations.
There are 8!/[6!(8-6)!] = 8*7/2 = 28 - too many to list.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
24C7 = 24!/((24-7)!7!) = 346,104.