The formula (21n) represents a sequence where (n) is a positive integer. To find the first five terms, substitute (n) with values from 1 to 5:
Thus, the first five terms are 21, 42, 63, 84, and 105.
They are 7, 10, 13, 16 and 19.
4, 6, 8, 10, 12
The sum of the first five terms of a geometric series can be calculated using the formula ( S_n = a_1 \frac{1 - r^n}{1 - r} ), where ( a_1 ) is the first term, ( r ) is the common ratio, and ( n ) is the number of terms. Here, ( a_1 = 6 ), ( r = 13 ), and ( n = 5 ). Substituting these values into the formula gives: [ S_5 = 6 \frac{1 - 13^5}{1 - 13} = 6 \frac{1 - 371293}{-12} = 6 \cdot \frac{-371292}{-12} = 6 \cdot 30939 = 185634 ] Thus, the sum of the first five terms is 185634.
The simplest formula is: t(n) = 2n + 5 for n = 1, 2, 3, ... However, that is not the only formula; there are infinitely many polynomial formulae that can be found that give those five terms first, but for the 6th or further terms vary.
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They are 7, 10, 13, 16 and 19.
They are 7, 10, 13, 16 and 19.
4, 6, 8, 10, 12
A single number, such as 3461018, does not make a pattern.
The sum of the first five terms of a geometric series can be calculated using the formula ( S_n = a_1 \frac{1 - r^n}{1 - r} ), where ( a_1 ) is the first term, ( r ) is the common ratio, and ( n ) is the number of terms. Here, ( a_1 = 6 ), ( r = 13 ), and ( n = 5 ). Substituting these values into the formula gives: [ S_5 = 6 \frac{1 - 13^5}{1 - 13} = 6 \frac{1 - 371293}{-12} = 6 \cdot \frac{-371292}{-12} = 6 \cdot 30939 = 185634 ] Thus, the sum of the first five terms is 185634.
All but John Adams served two terms. The total of the first five was nine terms or 36 years (almost - Washington's first term was about an month short.)
The simplest formula is: t(n) = 2n + 5 for n = 1, 2, 3, ... However, that is not the only formula; there are infinitely many polynomial formulae that can be found that give those five terms first, but for the 6th or further terms vary.
The sequence 4n + 7 represents a linear sequence where n is the position in the sequence. To find the first five terms, substitute n with 1, 2, 3, 4, and 5 respectively. Thus, the first five terms are 11, 15, 19, 23, and 27.
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2,1,0 is th sequence of its terms
The expression "n plus 3" can be represented as ( n + 3 ). To find the first five terms, we can substitute the values ( n = 1, 2, 3, 4, ) and ( 5 ) into the expression. The first five terms are: ( 1 + 3 = 4 ) ( 2 + 3 = 5 ) ( 3 + 3 = 6 ) ( 4 + 3 = 7 ) ( 5 + 3 = 8 ) Thus, the first five terms are 4, 5, 6, 7, and 8.
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